I'm almost positive I gave such an example in another thread recently... anyways:
IndexService index = new LuceneFulltextQueryIndexService( neo ); index.index( myNode1, "someKey", 150 ); index.index( myNode2, "someKey", 100 ); index.index( myNode3, "someKey", 170 ); index.index( myNode4, "someKey", 230 ); // This will return myNode1, myNode2 and myNode3 index.getNodes( "someKey", "[0 TO 170]" ); See http://lucene.apache.org/java/2_9_1/queryparsersyntax.html#Range%20Searches for more information. 2010/1/10 Zerony Zhao <[email protected]>: > Hi Neo4j Users, > > I have a naive question, since I just began learning Neo4j. > > I know how to find nodes where property key matchs value, > > indexService.getNodes(key, value); > > But I do not know the efficient way to find key < value, given the key is an > int property. In another thread, Tobias wrote several days ago: > > If your queries are as simple as "give me all nodes where x>LOWER_LIMIT and > x<UPPER_LIMIT ordered by x", and you can reduce the x property to a long > integer value. > > But I do not know how to , would you kindly give me a snapshot of code to > illustrate how to find all nodes where key < value. > > Appreciate your help. > > Zerony > _______________________________________________ > Neo mailing list > [email protected] > https://lists.neo4j.org/mailman/listinfo/user > -- Mattias Persson, [[email protected]] Neo Technology, www.neotechnology.com _______________________________________________ Neo mailing list [email protected] https://lists.neo4j.org/mailman/listinfo/user
