Hey,
> outE/outV # confusing way of saying (in XPath) "self::node()"
> inE/inV # ditto
.I suppose----but once you get to an edge, you need to specify where you want
to go next (the tail or the head of the edge).. ? The outE/V convention would
mean you have to know that you did outE the prior step to infer you mean the
head of the edge at the next step... no? If you really care, you can define a
path:
path forward
./outE/inV
end
path backward
./inE/outV
end
Then you can do:
./forward/forward/forward
:).
See ya,
Marko.
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