Hi,
>> Another possible use case is this: show me anyone connected to the user with
>> ID = 123 and sort those contacts by users with the most outgoing
>> relationships.
>
> SECOND SCENARIO:
> $m := g:map()
> $_g/V/outE/i...@id=123]/../..[g:op-value('+',$m,.,count(./outE))]
>
Actually, given that you know that 123 is what you care about, a more efficient
implementation would be:
$m := g:map()
g:id(123)/inE/outV[g:op-value('+',$m,.,count(./outE))]
g:sort($m,'value')
In other words, just work backwards from vertex 123. There is no need to loop
through all vertices.
Take care,
Marko.
http://markorodriguez.com
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