Hi, I have 2 kind of nodes (let's say A and B) which are related using a relation of type 'USES'. I want to count all the type A nodes which have only 1 relation to B type node and all the type A nodes which have more than one relation to B type node.
I am using neo4j server and I am currently trying to make a cypher request for that : it would look like that : start A=(id,object_type,"A") match (A)-[r:USES]->(B) where count(r)=1 return count(A) It is possible to make that kind of request with Cypher ? If not, how would you do it with Neo4j server ? Cheers, Guillaume ALLEE | Capgemini | BTech Toulouse </PRE><p style="font-family:arial;color:grey" style="font-size:13px">This message contains information that may be privileged or confidential and is the property of the Capgemini Group. It is intended only for the person to whom it is addressed. If you are not the intended recipient, you are not authorized to read, print, retain, copy, disseminate, distribute, or use this message or any part thereof. If you receive this message in error, please notify the sender immediately and delete all copies of this message.</p><PRE> _______________________________________________ Neo4j mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user