Thanks everyone, this gives me plenty to work with. Will report back.
On Thu, Sep 8, 2011 at 7:03 AM, Marko Rodriguez <[email protected]>wrote:
> Hey,
>
> > Won't this count dupes more than once?
> >
> > Xavier's requirements of "how many other nodes are they connected" sounds
> > like you should only count uniques, and that's why I am checking the size
> of
> > groupCount map instead of using count(). Instead of a map you could use a
> > Set with aggregate(), but I wasn't sure if they'd have the aggregate-loop
> > fix yet.
>
> Then add a uniqueObject to the pipeline.
>
> g.idx(index_name)[[key:value]].both.loop(1){it.loops <
> depth}.uniqueObject.count()
>
> > Also Xavier said, "For all nodes in a particular index". I took that to
> mean
> > all nodes in an index, not all nodes for a particular value in an index,
> > hence the wildcard query:
> >
> > index_nodes = g.idx(index_name).get(index_key,Neo4jTokens.QUERY_HEADER +
> > "*")
> >
> > However, I am not sure/can't remember if you can do a wildcard query
> without
> > at least one leading character.
>
>
> Oh.... then yea, the %query% header can be used.
>
> Marko.
>
> http://markorodriguez.com
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