You know me and my obsession for densely connected nodes :-)
> Date: Thu, 27 Oct 2011 17:37:07 +0000
> From: peter.neuba...@neotechnology.com
> To: user@lists.neo4j.org
> Subject: Re: [Neo4j] Function to check whether two nodes are connected?
>
> Good catch Niels, thanks - my brain is in jet lag mode :-\
> On Oct 27, 2011 7:26 PM, "Niels Hoogeveen" <pd_aficion...@hotmail.com>
> wrote:
>
> >
> > I see I made a bit of a mistake with this one. The gist of the solution
> > remains, but I made a mistake dealing with the directions of relationship.
> > It should be something like this.
> > public boolean areConnected(Node n1,Node n2, RelationshipType
> > relType,Direction dir) {
> >
> > Direction dir2 = null;
> > if(dir.equals(Direction.INCOMING))
> > dir2 = Direction.OUTGOING;
> > else if(dir.equals(Direction.OUTGOING))
> > dir2 = Direction.INCOMING;
> > else dir2 = Direction.BOTH;
> >
> > Iterator<Relationship> rels1 = n1.getRelationships(relType,
> > dir).iterator();
> > Iterator<Relationship> rels2 = n2.getRelationships(relType,
> > dir2).iterator();
> >
> > while(rels1.hasNext && rels2.hasNext){
> > Relationship rel1 = rels1.next();
> > Relationship rel2 = rels2.next();
> >
> > if (rel1.getEndNode().equals(n2)
> > return true;
> > else if (rel2.getEndNode().equals(n1))
> > return true;
> > }
> > return false;
> > }
> > > From: pd_aficion...@hotmail.com
> > > To: user@lists.neo4j.org
> > > Date: Thu, 27 Oct 2011 19:05:16 +0200
> > > Subject: Re: [Neo4j] Function to check whether two nodes are connected?
> > >
> > >
> > > There is one caveat to this method, you'd have to know which node is
> > most densely connected.
> > >
> > > Suppose one of the nodes has 100,000 relationships (incoming and
> > outgoing) and the other node has only a few relationships, then you'd want
> > to iterate over the relationships of the second node.
> > >
> > > A solution could be to iterate over both sets of relationships at the
> > same time:
> > >
> > > public boolean areConnected(Node n1,Node n2, RelationshipType
> > relType,Direction dir) {
> > >
> > > Iterator<Relatiionship> rels1 = n1.getRelationships(relType,
> > dir).iterator();
> > > Iterator<Relatiionship> rels2 = n2.getRelationships(relType,
> > dir).iterator();
> > >
> > > while(rels1.hasNext && rels2.hasNext){
> > > Relationship rel1 = rels1.next();
> > > Relationship rel2 = rels2.next();
> > >
> > > if (rel1.getEndNode().equals(n2)
> > > return true;
> > > else if (rel2.getEndNode().equals(n1))
> > > return true;
> > > }
> > > return false;
> > > }
> > > > Date: Thu, 27 Oct 2011 18:39:01 +0200
> > > > From: bplsi...@gmail.com
> > > > To: user@lists.neo4j.org
> > > > Subject: Re: [Neo4j] Function to check whether two nodes are connected?
> > > >
> > > > Easy: just one.
> > > >
> > > > For now, I've written this, but I'm still not sure it is the simplest
> > > > way to write it
> > > >
> > > > public boolean areConnected(Node n1,Node n2,Relationship
> > > > rel,Direction dir) throws Exception {
> > > > Iterable<Relationship> relationships =
> > n1.getRelationships(dir);
> > > >
> > > > for (Relationship r : relationships) {
> > > > //I am only working with Dynamic Relationships
> > > > if (r.getType().equals(rel.getType())) {
> > > > if (dir == Direction.OUTGOING) { if
> > > > (r.getEndNode().equals(n2)) { return true; } }
> > > > else { if (r.getStartNode().equals(n2)) { return
> > true; } }
> > > > }
> > > > }
> > > > return false;
> > > > }
> > > >
> > > > Bruno
> > > >
> > > > Le 27/10/2011 18:31, Peter Neubauer a écrit :
> > > > > Bruno,
> > > > > There is no such function low level, but toy can use a Shortest path
> > algo to
> > > > > check this. What is the maximum length for a path between the nodes?
> > > > > On Oct 27, 2011 6:14 PM, "Bruno Paiva Lima da Silva"<
> > bplsi...@gmail.com>
> > > > > wrote:
> > > > >
> > > > >> Hello there!
> > > > >> First of all, thanks for the help in all my previous questions, all
> > the
> > > > >> answers have been helping me to use Neo4j with success.
> > > > >>
> > > > >> I have a very simple question, but I haven't found the answer yet...
> > > > >>
> > > > >> I'd like to have a function, which signature would be more or less
> > like
> > > > >> this:
> > > > >>
> > > > >> public areTheyConnected(Node *n1*,Node *n2*,Relationship
> > *rel*,Direction
> > > > >> *dir*)
> > > > >>
> > > > >> which returns true iff there is an edge of type *rel*, between *n1*
> > and
> > > > >> *n2*, in the *dir* direction (the direction has n1 as reference).
> > > > >>
> > > > >> Example:
> > > > >>
> > > > >> In my graph, I have: "Bob knows Tom, Tom knows Peter, Jack knows
> > Tom"
> > > > >>
> > > > >> areTheyConnected(nodeBob,nodeTom,relKnows,Direction.OUTGOING)
> > returns
> > > > >> true; (Bob knows Tom)
> > > > >> areTheyConnected(nodeTom,nodeJack,relKnows,Direction.INCOMING) also
> > > > >> returns true; (Jack knows Tom)
> > > > >>
> > > > >> areTheyConnected(nodeBob,nodeTom,relKnows,Direction.INCOMING)
> > returns
> > > > >> false; (Tom doesn't know Bob)
> > > > >>
> > > > >> Is there an easy method (constant time, or close) for that?
> > > > >>
> > > > >> Thank you very much,
> > > > >> Bruno
> > > > >> _______________________________________________
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> > > > >>
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