Alan,
> Sounds like an A level maths question :)
ROTFL!
> One way of doing it - off the top of my head
Ahh, what kind of a head do you have?! ;-)
> 1. build an an array of the available articles
> $o = mgd_list_topic_articles(x)
> $a = array();
while ($o->>fetch()) $a[]= $o->id;
Maybe I should give up...
> 2. build a list of articles from that list (using random numbers?)
> function randomint($max = 100) {
> static $startseed = 0;
> if (!$startseed) {
> $startseed = (double)microtime()*getrandmax();
> srand($startseed);
> }
> return (rand()%$max);
> }
> $b=array()
> while (count($b)<4) {
> $n = randomint(count($a));
> if (!$b[$a[$n]]) $b[$a[$n]] = "USEME";
> }
Ok, I couldn't say that this looks great to me as I don't understand
anything here... Oh, wait, there is a four! :-) = four articles
displayed?
> 3. print them
> while (list($k,v) = each($b)) {
> mgd_get_article($k)
> // print it!
> }
Would that print all of them? Or just 4?
Would I put this whole list that way into my script? I.e. instead of
my old
> <?
> $article = mgd_list_topic_articles_all($topic_id); {
> $displayed = 0;
> while ($displayed < 4 && $article && $article->fetch()) {
> if (mgd_is_article_in_topic_tree(94, $article->id)) { continue; }
> if (mgd_is_article_in_topic_tree(111, $article->id)) { continue; }
> $displayed++;
> ?>
?
Where would I then put this part
> if (mgd_is_article_in_topic_tree(94, $article->id)) { continue; }
?
This is well beyond my comprehension, I must say :-( Thanks for your
patience!
Alexander
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