> > echo $snippet->code; > > displays some part of snippet and it depends what exactly is in it. > > You should have all snippet code in page source. > it DOES NOT.
I mean of course browser option "show source". > > And &(snippet.code:p); > > displays snippet's name....... > And even &(snippet.code); displays the code. That's what worries. Want to say that &(snippet.code); does while $snippet->code does not? Piotras --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
