> > echo $snippet->code;
> > displays some part of snippet and it depends what exactly is in it.
> > You should have all snippet code in page source.
> it DOES NOT.

I mean of course browser option "show source".

 
> > And &(snippet.code:p);
> > displays snippet's name.......
> And even &(snippet.code); displays the code. That's what worries.

Want to say that 
&(snippet.code); does while $snippet->code does not?

Piotras

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