Re: extract tuple from bag in an order

[Mehmet Tepedelenlioglu]

You could separate the inner bags, flatten, rank, and join. It would be ugly 
and inefficient though. It is best to just write a udf which basically does 
what the python’s zip function does.

On Jun 5, 2014, at 1:36 AM, Patcharee Thongtra <patcharee.thong...@uni.no> 
wrote:

> Hi,
> 
> I have the following data
> 
> (2009-09-09,2,1,{(70)},{(80)},{(90)})
> (2010-10-10,2,12,{(71),(75)},{(81),(85)},{(91),(95)})
> (2012-12-12,2,9,{(76),(77),(78)},{(86),(87),(88)},{(96),(97),(98)})
> 
> which is in the format
> 
> {date: chararray, zone: int, z: int, uTmp: {(varvalue: int)}, vTmp: 
> {(varvalue: int)}, thTmp: {(varvalue: int)} }
> 
> How can I get:
> 
> (2009-09-09,2,1,70,80,90)
> (2010-10-10,2,12,71,81,91)
> (2010-10-10,2,12,75,85,95)
> (2012-12-12,2,9,76,86,96)
> (2012-12-12,2,9,77,87,97)
> (2012-12-12,2,9,78,88,98)
> 
> Any suggestion is appreciated.
> 
> Patcharee
> 
> 
> 
>