Looking at what this patch [1] has to do to achieve it, I am not sure if you can do the same thing in 1.0.0 using DSL only. Just curious, why don't you use the hql() / sql() methods and pass a query string in?
[1] https://github.com/apache/spark/pull/1211/files On Thu, Jul 31, 2014 at 2:20 PM, Buntu Dev <buntu...@gmail.com> wrote: > Thanks Zongheng for the pointer. Is there a way to achieve the same in 1.0.0 > ? > > > On Thu, Jul 31, 2014 at 1:43 PM, Zongheng Yang <zonghen...@gmail.com> wrote: >> >> countDistinct is recently added and is in 1.0.2. If you are using that >> or the master branch, you could try something like: >> >> r.select('keyword, countDistinct('userId)).groupBy('keyword) >> >> On Thu, Jul 31, 2014 at 12:27 PM, buntu <buntu...@gmail.com> wrote: >> > I'm looking to write a select statement to get a distinct count on >> > userId >> > grouped by keyword column on a parquet file SchemaRDD equivalent of: >> > SELECT keyword, count(distinct(userId)) from table group by keyword >> > >> > How to write it using the chained select().groupBy() operations? >> > >> > Thanks! >> > >> > >> > >> > -- >> > View this message in context: >> > http://apache-spark-user-list.1001560.n3.nabble.com/SchemaRDD-select-expression-tp11069.html >> > Sent from the Apache Spark User List mailing list archive at Nabble.com. > >
