I think the behavior is by designed. Because if b is not persisted, and in each
call b.collect, broadcasted has point to a new broadcasted variable, serialized
by driver, and fetched by executors.
If you do persist, you don’t expect the RDD get changed due to new broadcasted
variable.
Thanks.
Zhan Zhang
On Aug 18, 2014, at 11:26 AM, Peng Cheng <pc...@uow.edu.au> wrote:
> I'm curious to see that if you declare broadcasted wrapper as a var, and
> overwrite it in the driver program, the modification can have stable impact
> on all transformations/actions defined BEFORE the overwrite but was executed
> lazily AFTER the overwrite:
>
> val a = sc.parallelize(1 to 10)
>
> var broadcasted = sc.broadcast("broad")
>
> val b = a.map(_ + broadcasted.value)
> // b.persist()
> for (line <- b.collect()) { print(line) }
>
> println("\n=======================================")
> broadcasted = sc.broadcast("cast")
>
> for (line <- b.collect()) { print(line) }
>
> the result is:
>
> 1broad2broad3broad4broad5broad6broad7broad8broad9broad10broad
> =======================================
> 1cast2cast3cast4cast5cast6cast7cast8cast9cast10cast
>
> Of course, if you persist b before overwriting it will still get the
> non-surprising result (both are 10broad... because they are persisted). This
> can be useful sometimes but may cause confusion at other times (people can
> no longer add persist at will just for backup because it may change the
> result).
>
> So far I've found no documentation supporting this feature. So can some one
> confirm that its a feature craftly designed?
>
> Yours Peng
>
>
>
> --
> View this message in context:
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