Hello Tridib,
For you case, you can use StructType(StructField("ParentInfo", parentInfo,
true) :: StructField("ChildInfo", childInfo, true) :: Nil) to create the
StructType representing the schema (parentInfo and childInfo are two
existing StructTypes). You can take a look at our docs (
http://spark.apache.org/docs/1.1.0/sql-programming-guide.html#programmatically-specifying-the-schema
and
http://spark.apache.org/docs/1.1.0/api/scala/index.html#org.apache.spark.sql.package
).
Thanks,
Yin
On Tue, Nov 4, 2014 at 3:19 PM, tridib <tridib.sama...@live.com> wrote:
> I am trying to create a schema which will look like:
>
> root
> |-- ParentInfo: struct (nullable = true)
> | |-- ID: string (nullable = true)
> | |-- State: string (nullable = true)
> | |-- Zip: string (nullable = true)
> |-- ChildInfo: struct (nullable = true)
> | |-- ID: string (nullable = true)
> | |-- State: string (nullable = true)
> | |-- Hobby: string (nullable = true)
> | |-- Zip: string (nullable = true)
>
> How do I create a StructField of StructType? I think that's what the "root"
> is.
>
> Thanks & Regards
> Tridib
>
>
>
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