the more scalable alternative is to do a join (or a variant like cogroup, leftOuterJoin, subtractByKey etc. found in PairRDDFunctions)
the downside is this requires a shuffle of both your RDDs On Thu, Feb 19, 2015 at 3:36 PM, Himanish Kushary <himan...@gmail.com> wrote: > Hi, > > I have two RDD's with csv data as below : > > RDD-1 > > 101970_5854301840,fbcf5485-e696-4100-9468-a17ec7c5bb43,19229261643 > 101970_5854301839,fbaf5485-e696-4100-9468-a17ec7c5bb39,9229261645 > 101970_5854301839,fbbf5485-e696-4100-9468-a17ec7c5bb39,9229261647 > 101970_17038953,546853f9-cf07-4700-b202-00f21e7c56d8,791191603 > 101970_5854301840,fbcf5485-e696-4100-9468-a17ec7c5bb42,19229261643 > 101970_5851048323,218f5485-e58c-4200-a473-348ddb858578,290542385 > 101970_5854301839,fbcf5485-e696-4100-9468-a17ec7c5bb41,922926164 > > RDD-2 > > 101970_17038953,546853f9-cf07-4700-b202-00f21e7c56d9,7911160 > 101970_5851048323,218f5485-e58c-4200-a473-348ddb858578,2954238 > 101970_5854301839,fbaf5485-e696-4100-9468-a17ec7c5bb39,9226164 > 101970_5854301839,fbbf5485-e696-4100-9468-a17ec7c5bb39,92292164 > 101970_5854301839,fbcf5485-e696-4100-9468-a17ec7c5bb41,9226164 > > 101970_5854301838,fbcf5485-e696-4100-9468-a17ec7c5bb40,929164 > 101970_5854301838,fbcf5485-e696-4100-9468-a17ec7c5bb39,26164 > > I need to filter RDD-2 to include only those records where the first > column value in RDD-2 matches any of the first column values in RDD-1 > > Currently , I am broadcasting the first column values from RDD-1 as a list > and then filtering RDD-2 based on that list. > > val rdd1broadcast = sc.broadcast(rdd1.map { uu => uu.split(",")(0) > }.collect().toSet) > > val rdd2filtered = rdd2.filter{ h => > rdd1broadcast.value.contains(h.split(",")(0)) } > > This will result in data with first column "101970_5854301838" (last two > records) to be filtered out from RDD-2. > > Is this is the best way to accomplish this ? I am worried that for large data > volume , the broadcast step may become an issue. Appreciate any other > suggestion. > > ----------- > Thanks > Himanish >