Here, println isn't happening on the driver. Are you sure you are
looking at the right machine's logs?
Yes this may be parallelized over many machines.
On Mon, Feb 23, 2015 at 6:37 PM, kvvt <kvi...@vt.edu> wrote:
> In the snippet below,
>
> graph.edges.groupBy[VertexId](f1).foreach {
> edgesBySrc => {
> f2(edgesBySrc).foreach {
> vertexId => {
> *println(vertexId)*
> }
> }
> }
> }
>
> "f1" is a function that determines how to group the edges (in my case it
> groups by source vertex)
> "f2" is another function that does some computation on the edges. It returns
> an iterable (Iterable[VertexId]).
>
> *Questions:*
>
> 1. The problem is that "println(vertexId)" doesn't printing anything. I have
> made sure that "f2" doesn't return an empty iterable. I am not sure what I
> am missing here.
>
> 2. I am assuming that "f2" is called for each group in parallel. Is this
> correct? If not, what is the correct way to operate on each group in
> parallel?
>
>
> Thanks!
>
>
>
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