Hi Satish,
You can refer the following code snippet:
df.select(concat(col("String_Column"), lit("00:00:000")))
Yanbo
2015-12-12 16:01 GMT+08:00 satish chandra j <jsatishchan...@gmail.com>:
> HI,
> I am trying to update a column value in DataFrame, incrementing a column
> of integer data type than the below code works
>
> val new_df=old_df.select(df("Int_Column")+10)
>
> If I implement the similar approach for appending a string to a column of
> string datatype as below than it does not error out but returns only
> "null" values
>
> val new_df=old_df.select(df("String_Column")+"00:00:000")
> OR
> val dt ="00:00:000"
> val new_df=old_df.select(df("String_Column")+toString(dt))
>
> Please suggest if any approach to update a column value of datatype String
> Ex: Column value consist '20-10-2015' post updating it should have
> '20-10-201500:00:000'
>
> Note: Transformation such that new DataFrame has to becreated from old
> DataFrame
>
> Regards,
> Satish Chandra
>
>
>
>
