Hello,
I have a such situation:
abstract class SuperType {...}
case class ChildTypeOne(x: String) extends SuperType {.....}
case class ChildTypeTwo(x: String) extends SuperType {....}
than I have:
val rdd1: RDD[SuperType] = sc./*some code*/.map(r => ChildTypeOne(r))
val rdd2: RDD[SuperType] = sc./*some code*/.map(r => ChildTypeTwo(r))
but when i try to:
def someFunction(rdd: RDD[SuperType]) = rdd match {
case rdd: RDD[ChildTypeOne] => println("ChildTypeOne")
case rdd: RDD[ChildTypeTwo] => println("ChildTypeTwo")
}
i get:
Error:(60, 15) pattern type is incompatible with expected type;
found : org.apache.spark.rdd.RDD[ChildTypeOne]
required: org.apache.spark.rdd.RDD[SuperType]
Note: ChildTypeOne <: SuperType, but class RDD is invariant in type T.
You may wish to define T as +T instead. (SLS 4.5)
case rdd: RDD[ChildTypeOne] => println("ChildTypeOne")
^
So how to work around it? Because in some situations I need to distinguish
them.
Best regards,
Pavel Khamutou
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