If you’re confident the schema of all files is consistent, then just infer the
schema from a single file and reuse it when loading the whole data set:
val schema = spark.read.json(“/path/to/single/file.json”).schema
val wholeDataSet = spark.read.schema(schema).json(“/path/to/whole/datasets”)
Thanks,
Silvio
On 10/16/17, 10:20 AM, "Jeroen Miller" <bluedasya...@gmail.com> wrote:
Hello Spark users,
Does anyone know if there is a way to generate the Scala code for a complex
structure just from the output of dataframe.printSchema?
I have to analyse a significant volume of data and want to explicitly set
the schema(s) to avoid having to read my (compressed) JSON files multiple
times. What I am doing so far is to read a few files, print the schema, and
manually write the code to define the corresponding StructType: tedious and
error-prone.
I'm sure there is a much better way, but can't find anything about it.
Pointers anyone?
Jeroen
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