Write a UDF?
> On Oct 31, 2017, at 11:48, Aakash Basu <aakash.spark....@gmail.com
> <mailto:aakash.spark....@gmail.com>> wrote:
>
> Hey all,
>
> Any help in the below please?
>
> Thanks,
> Aakash.
>
>
> ---------- Forwarded message ----------
> From: Aakash Basu <aakash.spark....@gmail.com
> <mailto:aakash.spark....@gmail.com>>
> Date: Tue, Oct 31, 2017 at 9:17 PM
> Subject: Regarding column partitioning IDs and names as per hierarchical
> level SparkSQL
> To: user <user@spark.apache.org <mailto:user@spark.apache.org>>
>
>
> Hi all,
>
> I have to generate a table with Spark-SQL with the following columns -
>
>
> Level One Id: VARCHAR(20) NULL
> Level One Name: VARCHAR( 50) NOT NULL
> Level Two Id: VARCHAR( 20) NULL
> Level Two Name: VARCHAR(50) NULL
> Level Thr ee Id: VARCHAR(20) NULL
> Level Thr ee Name: VARCHAR(50) NULL
> Level Four Id: VARCHAR(20) NULL
> Level Four Name: VARCHAR( 50) NULL
> Level Five Id: VARCHAR(20) NULL
> Level Five Name: VARCHAR(50) NULL
> Level Six Id: VARCHAR(20) NULL
> Level Six Name: VARCHAR(50) NULL
> Level Seven Id: VARCHAR( 20) NULL
> Level Seven Name: VARCHAR(50) NULL
> Level Eight Id: VARCHAR( 20) NULL
> Level Eight Name: VARCHAR(50) NULL
> Level Nine Id: VARCHAR(20) NULL
> Level Nine Name: VARCHAR( 50) NULL
> Level Ten Id: VARCHAR(20) NULL
> Level Ten Name: VARCHAR(50) NULL
>
> My input source has these columns -
>
>
> ID Description ParentID
> 10 Great-Grandfather
> 1010 Grandfather 10
> 101010 1. Father A 1010
> 101011 2. Father B 1010
> 101012 4. Father C 1010
> 101013 5. Father D 1010
> 101015 3. Father E 1010
> 101018 Father F 1010
> 101019 6. Father G 1010
> 101020 Father H 1010
> 101021 Father I 1010
> 101022 2A. Father J 1010
> 10101010 2. Father K 101010
>
> Like the above, I have ID till 20 digits, which means, I have 10 levels.
>
> I want to populate the ID and name itself along with all the parents till the
> root for any particular level, which I am unable to create a concrete logic
> for.
>
> Am using this way to fetch respecting levels and populate them in the
> respective columns but not their parents -
>
> Present Logic ->
>
> FinalJoin_DF = spark.sql("select "
> + "case when length(a.id <http://a.id/>)/2 = '1'
> then a.id <http://a.id/> else ' ' end as level_one_id, "
> + "case when length(a.id <http://a.id/>)/2 = '1' then
> a.desc else ' ' end as level_one_name, "
> + "case when length(a.id <http://a.id/>)/2 = '2' then
> a.id <http://a.id/> else ' ' end as level_two_id, "
> + "case when length(a.id <http://a.id/>)/2 = '2' then
> a.desc else ' ' end as level_two_name, "
> + "case when length(a.id <http://a.id/>)/2 = '3'
> then a.id <http://a.id/> else ' ' end as level_three_id, "
> + "case when length(a.id <http://a.id/>)/2 = '3'
> then a.desc else ' ' end as level_three_name, "
> + "case when length(a.id <http://a.id/>)/2 = '4'
> then a.id <http://a.id/> else ' ' end as level_four_id, "
> + "case when length(a.id <http://a.id/>)/2 = '4'
> then a.desc else ' ' end as level_four_name, "
> + "case when length(a.id <http://a.id/>)/2 = '5'
> then a.id <http://a.id/> else ' ' end as level_five_id, "
> + "case when length(a.id <http://a.id/>)/2 = '5'
> then a.desc else ' ' end as level_five_name, "
> + "case when length(a.id <http://a.id/>)/2 = '6'
> then a.id <http://a.id/> else ' ' end as level_six_id, "
> + "case when length(a.id <http://a.id/>)/2 = '6' then
> a.desc else ' ' end as level_six_name, "
> + "case when length(a.id <http://a.id/>)/2 = '7' then
> a.id <http://a.id/> else ' ' end as level_seven_id, "
> + "case when length(a.id <http://a.id/>)/2 = '7'
> then a.desc else ' ' end as level_seven_name, "
> + "case when length(a.id <http://a.id/>)/2 = '8'
> then a.id <http://a.id/> else ' ' end as level_eight_id, "
> + "case when length(a.id <http://a.id/>)/2 = '8' then
> a.desc else ' ' end as level_eight_name, "
> + "case when length(a.id <http://a.id/>)/2 = '9'
> then a.id <http://a.id/> else ' ' end as level_nine_id, "
> + "case when length(a.id <http://a.id/>)/2 = '9' then
> a.desc else ' ' end as level_nine_name, "
> + "case when length(a.id <http://a.id/>)/2 = '10'
> then a.id <http://a.id/> else ' ' end as level_ten_id, "
> + "case when length(a.id <http://a.id/>)/2 = '10'
> then a.desc else ' ' end as level_ten_name "
> + "from CategoryTempTable a")
>
>
> Can someone help me in also populating all the parents levels in the
> respective level ID and level name, please?
>
>
> Thanks,
> Aakash.
>
