hi,
thanks for your quick reply. i checked the code
it shows nothing.
code:
Object o = getParameters().get("partyid"); if (o instanceof String) {
System.out.println("String = " + o); } else if (o instanceof
String[]) { String[] a = (String[]) o; for(int i = 0; i
< a.length; i++) { System.out.println("String partyid:"+a[i]);
} }
output:
17:20:08,643 INFO [STDOUT] String partyid:
but the value is there
partyid=[Ljava.lang.String;@38bbd7}
i don't know why it doesn't shows ?
> Date: Sat, 4 Oct 2008 17:53:05 +0200> From: [EMAIL PROTECTED]> To:
> user@struts.apache.org> Subject: Re: ParameterAware Issue> > 2008/10/4 alley
> sys <[EMAIL PROTECTED]>:> > thanks for your mail. yeah it shows 1 value is
> there having address> > but i need the value not address> > I'm not sure if I
> understood you, but if it shows 1, you should be> able to access it as a
> array, but if it's only one element, OGNL> shouldn't create an array, maybe
> try something like this> > Object o = parameters.get("par");> if (o
> instanceof String) {> System.out.println("String = " + o);> } else if (o
> instanceof String[]) {> String[] a = (String[]) o;> for(int i = 0; i <
> a.length; i++) {> System.out.println(a[i]);> }> }> > > Regards> -- > Lukasz>
> http://www.lenart.org.pl/> >
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