>Use the *preferred* method, the interceptor.
It says:
Ensure that {{fileUpload }} Interceptor is included in the Action's stack.
.*The default stack already includes {{fileUpload }}.*
I don't know how to determine 'Ensure that {{fileUpload }} Interceptor is
included in the Action's stack",which file? Would you give me a example?
By the way, I want to get upload stream as follows:
FileInputStream fis = ... //how to get FileInputStream?
uploadaction.setData(Hibernate.createBlob(fis));
My question is how to get upload stream when submit jsp to action, client
and server are not the same machine. How to do it? An example is better.
phoenix
On Tue, Dec 16, 2008 at 11:32 PM, Dave Newton <newton.d...@yahoo.com> wrote:
> Use the *preferred* method, the interceptor.
>
> I haven't looked in to what caused the breaking change.
>
> Dave
>
> --- On Tue, 12/16/08, red phoenix <rodphoe...@gmail.com> wrote:
>
> > From: red phoenix <rodphoe...@gmail.com>
> > Subject: Re: org.apache.struts2.dispatcher.StrutsRequestWrapper cannot be
> cast to org.apache.struts2.dispatcher.multipart.MultiPartRequestWrapper
> > To: "Struts Users Mailing List" <user@struts.apache.org>,
> newton.d...@yahoo.com
> > Date: Tuesday, December 16, 2008, 10:26 AM
> > In
> > http://struts.apache.org/2.0.14/docs/how-do-we-upload-files.html
> > , it use
> > MultiPartRequestWrapper multipartRequest =
> > (MultiPartRequestWrapper)
> > ServletActionContext.getRequest();
> > It still raise java.lang.ClassCastException:
> > org.apache.struts2.dispatcher.StrutsRequestWrapper cannot
> > be cast to
> > org.apache.struts2.dispatcher.multipart.MultiPartRequestWrapper.
> > My popuse is that when jsp sumbit to action,I can get
> > upload file name and
> > the stream of upload file,then I can write the stream of
> > upload file into
> > blob of oracle database.I don't know how to get the
> > stream of upload file!
> > I still puzzled with why raise above error. I don't
> > find the different
> > between my code and
> > http://struts.apache.org/2.0.14/docs/how-do-we-upload-files.html.
> >
> > Where wrong with my code?
> >
> >
> >
> >
> > On Tue, Dec 16, 2008 at 11:13 PM, Dave Newton
> > <newton.d...@yahoo.com> wrote:
> >
> > > --- On Tue, 12/16/08, red phoenix wrote:
> > > > [...]
> > > > MultiPartRequestWrapper multipartRequest =
> > > > (MultiPartRequestWrapper)
> > ServletActionContext.getRequest();
> > > > [...]
> > > >
> > > >
> > org.apache.struts2.dispatcher.StrutsRequestWrapper cannot be
> > cast to
> > > >
> > org.apache.struts2.dispatcher.multipart.MultiPartRequestWrapper
> > > >
> > > > Why raise above error?
> > >
> > > Because StrutsRequestWrappers can't be cast to
> > MultiPartRequestWrappers.
> > >
> > > > How to correct it?
> > >
> > > Use the built-in file upload capabilities of Struts 2;
> > there's no reason to
> > > access the request manually.
> > >
> > > Here's that link again:
> > >
> > >
> > http://struts.apache.org/2.0.14/docs/how-do-we-upload-files.html
> > >
> > > Dave
> > >
> > >
> > >
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> > user-h...@struts.apache.org
> > >
> > >
>
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