Martin Gainty wrote:
yes the Struts 1.x if tag has been deprecated
you can check for specific attributes as wes suggested
OR
change your struts-spring autowire type to "constructor" in your interceptor
stack e.g.
\WEB-INF\src\java\struts.xml
<interceptors>
<interceptor name="autowire"
class="com.opensymphony.xwork.spring.interceptor.ActionAutowiringInterceptor">
<param name="autowireStrategy">2</param>
</interceptor>
<interceptor-stack name="autowireDefault">
<interceptor-ref name="autowire"/>
<interceptor-ref name="defaultStack"/>
</interceptor-stack>
</interceptors>
and configure the springframework ContextLoaderListener in web.xml
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
where the individual bean has been configured as
<bean name="some-action" class="fully.qualified.class.name" singleton="false">
</bean>
take a brief look at the characteristics of your Bean class from Bean.java
public boolean start(Writer writer) {
boolean result = super.start(writer);
ValueStack stack = getStack();
try {
String beanName = findString(name, "name", "Bean name is required.
Example: com.acme.FooBean");
bean = objectFactory.buildBean(ClassLoaderUtil.loadClass(beanName,
getClass()), stack.getContext());
} catch (Exception e) {
LOG.error("Could not instantiate bean", e);
return false;
}
// push bean on stack
stack.push(bean);
...
}
that last statement stack.push(bean) means the bean is now on the stack to test
with!
from jsp
<s:property value="#beanname" />
we now know the bean as a constructed Bean object
(via the decorated name of the bean)
feel free to use the stack.push to push the necessary value to be accessed
later by <s:property ... /> in your jsp..
Seems like it'd be way easier just to expose it as an action property.
Dave
---------------------------------------------------------------------
To unsubscribe, e-mail: user-unsubscr...@struts.apache.org
For additional commands, e-mail: user-h...@struts.apache.org
