I guess not even pass as a query string, he needs to pick up the URL from the request object:
request.getRequestURL() Best, On Thu, Mar 17, 2011 at 3:33 PM, Okan Özeren <okanoze...@gmail.com> wrote: > Hi, > > I mean, you want to get a parameter as passed with original url by > query string. Am I right? You sould use this implementation: > > // Get the action context from the invocation so we can access the > // HttpServletRequest and HttpServletResponse objects. > final ActionContext context = invocation.getInvocationContext(); > HttpServletRequest request = (HttpServletRequest) > context.get(StrutsStatics.HTTP_REQUEST); > String param = request.getParameter("param"); > > Okan Özeren. > > On Thu, Mar 17, 2011 at 8:48 PM, Alfredo Manuel Osorio Martinez > <alfredo.oso...@afirme.com> wrote: > > I am implementing a Login interceptor which needs to redirect to an > > action to first authenticate the user. The problem is that I want to > > send as a parameter to that action the original url, the one that the > > user was trying to get before the redirect to the login page. > > > > > > > > How can I achieve that? > > > > > > > > Thanks in advance, > > > > > > > > Alfredo Osorio > > > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: user-unsubscr...@struts.apache.org > For additional commands, e-mail: user-h...@struts.apache.org > > -- Confidentiality Notice ------------------------------- THIS INFORMATION IS INTENDED ONLY FOR THE USE OF THE ADDRESSEE AND MAY CONTAIN INFORMATION THAT IS PRIVILEGED, CONFIDENTIAL AND EXEMPT FROM DISCLOSURE UNDER APPLICABLE LAW. IF YOU ARE NOT THE INTENDED RECIPIENT, OR THE EMPLOYEE OR AGENT RESPONSIBLE FOR DELIVERING THIS MESSAGE TO THE INTENDED RECIPIENT, YOU ARE HEREBY NOTIFIED THAT ANY DISSEMINATION, DISTRIBUTION OR COPYING OF THE COMMUNICATION IS STRICTLY PROHIBITED. IF YOU HAVE RECEIVED THIS COMMUNICATION IN ERROR, PLEASE NOTIFY IMMEDIATELY AT tutti...@gmail.com OR BY TELEPHONE AT 817-458-1764. THANK YOU.