Hi Abraham, Here I have few findings and suggestions for the spring namespace and application Context issues.
*For Spring Namespace Issue:* As per my earlier comments, the custom XML tags like <sca:service>, <sca:reference> and <sca:property> and the sca namespace will be supported only when Tuscany creates the application context for you. The reason is Tuscany not only defines the bean definition for these tags, but also defines the logic. So I believe Tuscany does the right thing to handle the sca namespace. A detailed article on how you would go about writing your own custom XML bean definition parsers and integrating such parsers into the Spring IoC container can be found here.... http://static.springframework.org/spring/docs/2.5.x/reference/extensible-xml.html *Loading Application Context using ClassPathXmlApplicationContext:* Defining a bean as shown below, <bean id="beanRefFactory" class="org.springframework.context.support.ClassPathXmlApplicationContext"> <constructor-arg><list> <value>Organization-spring-context.xml</value> </list></constructor-arg> </bean> would also result in a namespace issue being thrown, as in this case an application context is being created using ClassPathXmlApplicationContext (which is not aware of the sca namespace handlers). Here I have a question to ask, may be I am not good at spring, basically I am trying to understand what is the special purpose for using the ClassPathXmlApplicationContext to load the Organization-spring-context.xml file, while by default Tuscany would create the application context for this file when its been specified as <implementation.spring location="Organization-spring-context.xml"/> in the composite file? Your Comments on this would help us to come up with a better solution. *Accessing the Application Context:* Trying to load an application context using the code shown below, ApplicationContext applicationContext = (ApplicationContext) ContextSingletonBeanFactoryLocator.getInstance("beanRefFactory.xml").useBeanFactory("beanRefFactory").getFactory(); to access the beans would also result in a namespace issue for the same reason shown above. I believe there is a workaround to this problem, which demostrates how the runtime instance of the application context can be accessed and also get access to the beans as shown here..... http://blog.jdevelop.eu/2008/07/06/access-the-spring-applicationcontext-from-everywhere-in-your-application/ This solution returns the SCAApplicationContext instance which resolves the namespace for you. Probably, you need to evaluate if this workaround helps your scenario. Please provide us with your feedback on the same and let me know if I am missing something in this whole discussion. On Fri, Aug 29, 2008 at 10:04 PM, Abraham Washington <[EMAIL PROTECTED]>wrote: > hi Ramkumar...thx for helping out. > > > > https://issues.apache.org/jira/browse/TUSCANY-2573 > > > > thx abe > > > > > ----- Original Message ---- > From: Ramkumar R <[EMAIL PROTECTED]> > To: [email protected] > Sent: Friday, August 29, 2008 1:08:03 AM > Subject: Re: sca namespace in spring > > Hi Abraham, > Can you please raise a JIRA stating the namespace issue and the application > context issue? I like to take it up and see what best can be done here. > > > On Fri, Aug 15, 2008 at 12:58 AM, Abraham Washington <[EMAIL PROTECTED] > > wrote: > >> thanks for the info. appeciate it. i tried to reference the xsd >> locally, but it's throwing a "no declaration can be found for sca:service" >> error. >> >> >> >> < >> beans xmlns="http://www.springframework.org/schema/beans" >> >> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" >> >> xmlns:sca="http://www.springframework.org/schema/sca" >> >> xsi:schemaLocation=" >> >> http://www.springframework.org/schema/beans >> http://www.springframework.org/schema/beans/spring-beans.xsd >> >> >> http://www.springframework.org/schema/sca=C:\development\Organization-Service-Composite\src\main\resources\spring-sca.xsd<http://www.springframework.org/schema/sca=C:%5Cdevelopment%5COrganization-Service-Composite%5Csrc%5Cmain%5Cresources%5Cspring-sca.xsd> >> " >> > >> >> <sca:service name="OrganizationService" >> >> type="org.soa.services.OrganizationService" target= >> "OrganizationServiceBean"/> >> >> >> i'll keep trying..thx abe >> >> >> ----- Original Message ---- >> From: Mike Edwards <[EMAIL PROTECTED]> >> To: [email protected] >> Sent: Thursday, August 14, 2008 6:50:26 AM >> Subject: Re: sca namespace in spring >> >> Abe, >> >> I wondered why your case was different to that of the Spring tests - the >> spring-sca.xsd is present >> in Tuscany at this location: >> >> >> \java\sca\modules\implementation-spring\src\main\resources\org\springframework\sca\xml >> >> The file is also present in: >> >> tuscany-implementation-spring-1.4-SNAPSHOT.jar >> >> I'm sure that the Spring tests get the xsd from one of these. >> >> You're right in that the location >> >> http://www.springframework.org/schema/sca/spring-sca.xsd >> >> ...does not work. We shall have to fix the spec for this. >> >> You might try arranging to remove the current location definition and put >> the xsd in some local >> place that can be accessed when you run your application. >> >> >> Yours, Mike. >> >> >> >> Abraham Washington wrote: >> > hi all...no luck no matter which way i try. has anyone had any success >> > getting the application context using spring has an implementation. not >> >> > sure how I can get a bean if I can't get the application context. >> > >> > >> > >> > thx abe >> > >> > >> > >> > ----- Original Message ---- >> > From: Abraham Washington <[EMAIL PROTECTED]> >> > To: [email protected] >> > Sent: Monday, August 11, 2008 12:24:12 PM >> > Subject: Re: sca namespace in spring >> > >> > Running it in eclipse using scadomain. sca-1.3. spring 2.0.1. >> > >> > >> > >> > when i make the call to get the application context, it hurls. here's >> > my beanRefFactory.xml >> > >> > >> > >> > <beans> >> > >> > <bean id="beanRefFactory" >> > >> > >> class="org.springframework.context.support.ClassPathXmlApplicationContext"> >> > >> > <constructor-arg> >> > >> > <list> >> > >> > <value>Organization-spring-context.xml</value> >> > >> > </list> >> > >> > </constructor-arg> >> > >> > </bean> >> > >> > </beans> >> > >> > >> > >> > here's my call to get the applicationContext: >> > >> > >> > org.springframework.context.ApplicationContext applicationContext = >> > >> > (org.springframework.context.ApplicationContext) >> > >> org.springframework.context.access.ContextSingletonBeanFactoryLocator./getInstance/("beanRefFactory.xml").useBeanFactory("beanRefFactory").getFactory(); >> > >> > >> > >> > >> > thx abe >> >> > > > -- > Thanks & Regards, > Ramkumar Ramalingam > > -- Thanks & Regards, Ramkumar Ramalingam
