On 01.08.2015, at 23:06, Martin Wunderlich <[email protected]> wrote:
> Yes, I think you might be right, Richard, and that the problem is with the
> use of Generics.
>
> This would be the concrete FE class:
>
> public class StartingPositionOfPremiseUFE<Premise> extends
> StartingPositionOfPropositionUFE {
>
> public static String FN_STARTINGPOSITIONOFPROPOSITION =
> "StartingPositionOfPremise";
>
> @Override
> List<Premise> getPropositions(JCas jcas, int start, int end) {
> return JCasUtil.selectCovered(jcas, Premise.class, start, end);
> }
> }
I don't see why you would define <Premise> here on the subclass. You would
either define a type variable on the subclass or bind a type variable on the
superclass, so:
public class StartingPositionOfPremiseUFE extends
StartingPositionOfPropositionUFE<Premise>
> The call to selectCovered(…) gives the described error. The method
> getPropositions(…) is defined as abstract in the super-class, which looks
> like this:
>
>
> abstract public class StartingPositionOfPropositionUFE<T extends Proposition>
> extends FeatureExtractorResource_ImplBase implements
> ClassificationUnitFeatureExtractor{
> ...
> public List<Feature> extract(JCas jcas, TextClassificationUnit
> classificationUnit) {
> List<? extends Proposition> props = (List<? extends Proposition>)
> getPropositions(jcas, start, end);
Instead of <? extends Proposition>, I think you should be using <T>.
> if( props != null && props.size() > 0) {
> Proposition firstProposition = props.get(0);
> startingPos = firstProposition.getBegin();
> }
>
> List<Feature> featList = new ArrayList<Feature>();
> featList.add(new Feature(FN_STARTINGPOSITIONOFPROPOSITION,
> startingPos));
>
> return featList;
> }
>
> abstract List<?> getPropositions(JCas jcas, int start, int end);
Again, instead of <?> I think you should be using <T>.
> }
>
> I’ve removed the irrelevant bits to make it more concise.
I still don't see why you would get that error though.
Are you sure that "Premise.class" resolves to the right class here and not to
another class which accidentally has the same name?
-- Richard
