hello,when I run usergrid-rest
access link:http://localhost:8080/usergrid-rest/status
response:
{
"error": "uncaught", "timestamp": 1445572529016, "duration": 119, "exception":
"org.apache.usergrid.rest.exceptions.UncaughtException", "error_description":
"Internal Server Error", "error_id": "e664f258-7939-11e5-954f-a41731054ba5"
}
console error:
2015-10-23 11:48:08,110 ERROR
(Notifications_Processor026b090c-7518-417a-b0c9-0bfd6b036866)
[org.apache.usergrid.services.ServiceManager] - Failed to get application
java.lang.RuntimeException: application id
{b6768a08-b5d5-11e3-a495-11ddb1de66c8} is returning null
at
org.apache.usergrid.services.ServiceManager.init(ServiceManager.java:103)
at
org.apache.usergrid.services.ServiceManagerFactory.getServiceManager(ServiceManagerFactory.java:69)
at
org.apache.usergrid.services.notifications.QueueListener.execute(QueueListener.java:147)
at
org.apache.usergrid.services.notifications.QueueListener.access$0(QueueListener.java:137)
at
org.apache.usergrid.services.notifications.QueueListener$1.run(QueueListener.java:123)
at java.util.concurrent.Executors$RunnableAdapter.call(Unknown Source)
at java.util.concurrent.FutureTask.run(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
at java.util.concurrent.ThreadPoolExecuto
Environment:
usergrid : 2.1 release
cassandra : apache-cassandra-2.1.8
web server: tomcat 7
uuid define:
i find this define on org.apache.usergrid.corepersistence.util.CpNamingUtils,
public static final UUID MANAGEMENT_APPLICATION_ID = UUID.fromString(
"b6768a08-b5d5-11e3-a495-11ddb1de66c8" );
other:
if has demo cql for cassandra,can you tell me ? I create cassandra keyspaces
like usergrid docs,but error is alwith appear.
this error probably I missing column family data,but I try more times ,but No
solution,so I Seek help,hope get you help,thanks.
