Thanks for that! Other discussion in comments to VELOCITY-587.
jon.
On Feb 12, 2008 3:45 AM, Nathan Bubna <[EMAIL PROTECTED]> wrote:
> #set( $backslash = '\.' )
>
>
> On Feb 10, 2008 3:05 AM, Jon Seymour <[EMAIL PROTECTED]> wrote:
> > I am trying to write an expression that looks takes "abc.def.ghi" in
> > $package and rewrites it as abc/def/ghi, using Java 1.4 [ hence I
> > can't use String.replace ].
> >
> > #set($path=$package.replaceAll("\.", "/"))
> >
> > however, this doesn't work because \. results in a lexical error
> > during parsing template.
> >
> > Using "\\." doesn't work because "\\." is a string of 3 characters - \, \, .
> >
> > In the end, I had to do this:
> >
> > #set($tmp="\\.")
> > #set($path=$package.replaceAll($tmp.substring(1,3), "/"))
> >
> > but this seems like a kludge.
> >
> > Anyone got a neater way to express the string of characters {
> > backslash, period } in VTL?
> >
> > jon.
> >
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