Imorales, I think what you want is to automatically convert a POJO into an XML string, right? That way, you can convert the XML string into an XmlObject?
Not sure why you need to do that if you can already work with the POJO directly. Other than that, as Paul pointed out, you can use XStream to automatically deserialize your POJO to XML. Then, you should be able to convert the XML into an untyped XmlObject. But, you probably would only use the XmlObject for traversing the XML tree. You won't have methods like getB() and setB() since you aren't generating the XmlObject from a predefined schema. -----Original Message----- From: Paul French [mailto:[EMAIL PROTECTED] Sent: Tuesday, November 06, 2007 11:53 AM To: user@xmlbeans.apache.org Subject: RE: xmlbeans beginner - help XStream does exactly what you want. Paul -----Original Message----- From: Wing Yew Poon [mailto:[EMAIL PROTECTED] Sent: 06 November 2007 19:34 To: user@xmlbeans.apache.org Subject: RE: xmlbeans beginner - help imorales, I think you're looking for something that XMLBeans is not designed for. It sounds like you want to start with a POJO class and somehow automagically get something like an XmlObject out of it. There is no mechanism to do that. What Cezar wrote about is the capability of XMLBeans to parse xml without a schema to get an untyped XmlObject. So if you are getting xml from somewhere, you can turn that xml into an XmlObject. But it sounds like you're looking for something else. - Wing Yew -----Original Message----- From: imorales [mailto:[EMAIL PROTECTED] Sent: Tuesday, November 06, 2007 7:41 AM To: user@xmlbeans.apache.org Subject: RE: xmlbeans beginner - help Yes I know but, can I convert a simple java class A to a XmlObject without schema ? Albert Bupp wrote: > > He means the XmlObject class which you'll find in the XmlBeans library. > > -Albert > > At 10:27 AM 11/6/2007, you wrote: > >>That sounds good but, I don´t have a XmlObject, I have a simple pojo (class >>A) and i want to convert it to XmlObject, my class A have to implements >>XmlObject ? How can I do this ?? >> >>Cezar Andrei wrote: >> > >> > It is possible, but a little less forward that using schema. Just use >> > XmlObject, it handles all un-typed XML in XMLBeans. >> > >> > Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml >> into >> > XmlObject. >> > And String xmlText = xo.xmlText() to get back to xml. >> > >> > To navigate/read/modify the XmlObject without a schema, you have to use >> > either the cursor xo.newCursor() or the DOM xo.newDomNode(). >> > >> > Cezar >> > >> >> -----Original Message----- >> >> From: imorales [mailto:[EMAIL PROTECTED] >> >> Sent: Tuesday, November 06, 2007 8:50 AM >> >> To: user@xmlbeans.apache.org >> >> Subject: RE: xmlbeans beginner - help >> >> >> >> >> >> Is there any way to get from Java classes without XML schema and vice >> >> versa? >> >> >> >> Thanks. >> >> >> >> Schalk Neethling-4 wrote: >> >> > >> >> > You will more then likely have to start with a schema. So define >> your >> >> > schema and the from this generate your XMLBean which will give you >> >> object >> >> > A, you can then populate object A using the set methods that will be >> >> > generated and once you have the completed object you can invert it >> into >> >> a >> >> > XML string with one step by calling A.xmlText(); >> >> > >> >> > HTH! >> >> > >> >> > Regards, >> >> > Schalk Neethling >> >> > >> >> > -----Original Message----- >> >> > From: imorales [mailto:[EMAIL PROTECTED] >> >> > Sent: 06 November 2007 11:29 AM >> >> > To: user@xmlbeans.apache.org >> >> > Subject: xmlbeans beginner - help >> >> > >> >> > >> >> > Hi is my first time using xmlbeans and I hava a couple of question, >> I >> >> > explain >> >> > my scenario and I would like someone to resolve my ignorance about >> >> > xmlbeans. >> >> > >> >> > Well I hava a pojo class: >> >> > >> >> > ------------------------------------------ >> >> > public class A{ >> >> > private String b; >> >> > >> >> > public A(){} >> >> > >> >> > public String getB(){ return b;} >> >> > public void setB(String b){this.b = b;} >> >> > } >> >> > ------------------------------------------ >> >> > >> >> > I´m using a web service that takes one parameter (String), this >> >> parameter >> >> > is >> >> > the XML associated to the class A. My question is how I can using >> >> xmlbeans >> >> > conver one object A to a XML and then to String. I have no schema to >> do >> >> > this >> >> > and I don´t know if is necessary. >> >> > >> >> > Thanks in advance. >> >> > >> >> > -- >> >> > View this message in context: >> >> > >> http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299 >> >> > Sent from the Xml Beans - User mailing list archive at Nabble.com. >> >> > >> >> > >> >> > >> --------------------------------------------------------------------- >> >> > To unsubscribe, e-mail: [EMAIL PROTECTED] >> >> > For additional commands, e-mail: [EMAIL PROTECTED] >> >> > >> >> > >> >> > This email and all content are subject to the following disclaimer: >> >> > >> >> > http://content.momentum.co.za/content/legal/disclaimer_email.htm >> >> > >> >> > >> >> > >> >> > >> --------------------------------------------------------------------- >> >> > To unsubscribe, e-mail: [EMAIL PROTECTED] >> >> > For additional commands, e-mail: [EMAIL PROTECTED] >> >> > >> >> > >> >> > >> >> >> >> -- >> >> View this message in context: >> http://www.nabble.com/xmlbeans-beginner--- >> >> help-tf4756991.html#a13608035 >> >> Sent from the Xml Beans - User mailing list archive at Nabble.com. >> >> >> >> >> >> --------------------------------------------------------------------- >> >> To unsubscribe, e-mail: [EMAIL PROTECTED] >> >> For additional commands, e-mail: [EMAIL PROTECTED] >> > >> > >> > Notice: This email message, together with any attachments, may contain >> > information of BEA Systems, Inc., its subsidiaries and affiliated >> > entities, that may be confidential, proprietary, copyrighted and/or >> > legally privileged, and is intended solely for the use of the >> individual >> > or entity named in this message. If you are not the intended recipient, >> > and have received this message in error, please immediately return this >> by >> > email and then delete it. >> > >> > --------------------------------------------------------------------- >> > To unsubscribe, e-mail: [EMAIL PROTECTED] >> > For additional commands, e-mail: [EMAIL PROTECTED] >> > >> > >> > >> >>-- >>View this message in context: >>http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a1360887 5 >>Sent from the Xml Beans - User mailing list archive at Nabble.com. >> >> >>--------------------------------------------------------------------- >>To unsubscribe, e-mail: [EMAIL PROTECTED] >>For additional commands, e-mail: [EMAIL PROTECTED] > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > > -- View this message in context: http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13609293 Sent from the Xml Beans - User mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] Notice: This email message, together with any attachments, may contain information of BEA Systems, Inc., its subsidiaries and affiliated entities, that may be confidential, proprietary, copyrighted and/or legally privileged, and is intended solely for the use of the individual or entity named in this message. 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