Sorry, typo - the query should have been "declare default element namespace 'mynamespace'; /a/b".
________________________________ From: Wing Yew Poon [mailto:[EMAIL PROTECTED] Sent: Friday, February 22, 2008 11:11 AM To: user@xmlbeans.apache.org Subject: RE: Applying XPath to an XML with or without namespace Pascal, in <a xmlns="mynamespace"> <b/> </a> what you have is every element within and including a being qualified as having the namespace "mynamespace". Thus, the XPath must qualify the elements too. This is only logical. There are a couple of ways you can qualify the elements in the XPath. You can use the prolog you have in "declare namespace xs='mynamespace';/xs:a/xs:b"; you can also use "declare default namespace 'mynamespace; /a/b". The bottom line is that the path must follow the structure of the document. If elements/attributes are namespace-qualified in the document, then they must be too in the path. - Wing Yew ________________________________ From: Pascal Maugeri [mailto:[EMAIL PROTECTED] Sent: Friday, February 22, 2008 8:40 AM To: user@xmlbeans.apache.org Subject: Applying XPath to an XML with or without namespace Hi I would like to have some clarifications on how to apply XPath query on a XML document depending if it comes with or without a namespace definition. When I run the following code executing the XPath query /a/b on a document with no namespace: String doc = "<a><b/></a>"; String query = "/a/b"; XmlObject xml = XmlObject.Factory.parse(doc); XmlCursor cursor = xml.newCursor(); cursor.push(); cursor.selectPath(query); it gives me the correct result (<c/>). But if if the document comes with a namespace, for instance: <a xmlns="mynamespace"> <b/> </a> the same code does not give me any result. After investigating I found that a working code could be: String doc = "<a xmlns="mynamespace"><b/></a>"; String query = "declare namespace xs='mynamespace';/xs:a/xs:b"; XmlObject xml = XmlObject.Factory.parse(doc); XmlCursor cursor = xml.newCursor(); cursor.push(); cursor.selectPath(query); Is there a better way to do this without having to set the prefix "xs:" in the Xpath query for each level ? I would like to find a generic way to handle XML documents with or without namespace. Regards, Pascal Notice: This email message, together with any attachments, may contain information of BEA Systems, Inc., its subsidiaries and affiliated entities, that may be confidential, proprietary, copyrighted and/or legally privileged, and is intended solely for the use of the individual or entity named in this message. If you are not the intended recipient, and have received this message in error, please immediately return this by email and then delete it. Notice: This email message, together with any attachments, may contain information of BEA Systems, Inc., its subsidiaries and affiliated entities, that may be confidential, proprietary, copyrighted and/or legally privileged, and is intended solely for the use of the individual or entity named in this message. If you are not the intended recipient, and have received this message in error, please immediately return this by email and then delete it.
