Hopefully that works with XMLBeans because prefix declarations are maintained
:-)
But this won't:
<foo
xmlns="http://foobaz"/>
because insignificant space is not tracked. When the documentation refers to
the "original, native XML structure", it means the XML structure as defined by
the XML and XML Infoset specifications. But there are a few things which are
not significant in XML (like the spaces above, or when character references or
entities are used vs the characters themsleves) that XMLBeans doesn't keep
track of. There aren't that many, because XMLBeans goes beyond the letter of
the specifications, but in a large document, chances to hit one of these is
large.
If you want to use XML with digital signatures, there are specs that describe
how to do it (taking particularities of XML into account) and, though I have
not tried it myself, I have seen messages on this list from people who have
tried and apparently had some success.
One more think, you can try setting XmlOptions.setCDataBookmarks() to eliminate
one more potential source of differences, but for a robust solution you need to
look at the "XML Signature" spec.
Radu
________________________________
From: Jacob Danner [mailto:[EMAIL PROTECTED]
Sent: Monday, September 15, 2008 8:27 AM
To: [email protected]
Subject: Re: Very simple question (I think)
For XML to be equivalent, things like namespace prefixes, whitespace*,
etc can be different. With Strings, this is not the case.
For example:
<foo xmlns="http://foobaz"; />
and
<baz:foo xmlns:baz="http://foobaz"; />
Are equivalent in XML.
If you are hoping to do an == check using the above with strings it
will ALWAYS fail with String.equals.
Why not try
XMLObject.[compareTo|compareValue|valueEquals]
?
-jacobd
On Mon, Sep 15, 2008 at 7:14 AM, Nicolai Odum <[EMAIL PROTECTED]> wrote:
Sorry - but no good
From the javadoc
toString
String
<http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.html> toString()
Returns an XML string for this XML object.
The string is pretty-printed. If you want a non-pretty-printed
string, or if you want to control options precisely, use the xmlText() methods.
/Nicolai
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"Andrew Mansfield" <[EMAIL PROTECTED]>
15-09-2008 16:13
Please respond to
[email protected]
To
<[email protected]>
cc
Subject
RE: Very simple question (I think)
try parse.toString();
________________________________
From: Nicolai Odum [mailto:[EMAIL PROTECTED]
Sent: 15 September 2008 15:09
To: [email protected]
Subject: RE: Very simple question (I think)
I will try again :-)
Sorry for my pore english skills.
When I say invalid i mean that the generated hash value no
longer is valid...I can work with the xml beans structure but I need acces to
the untouched, native, raw xml string that I used as a argument to the factory.
XmlObject parse = XmlObject.Factory.parse(xml);
/Nicolai
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"Andrew Mansfield" <[EMAIL PROTECTED]>
15-09-2008 15:58
Please respond to
[email protected]
To
<[email protected]>
cc
Subject
RE: Very simple question (I think)
I just ran the following Junit test with no problems...
public void test() throws XmlException, IOException{
String xmltext = new
String("<test><element1>testvalue</element1></test>");
XmlObject xmlObject = XmlObject.Factory.parse(new
ByteArrayInputStream(xmltext.getBytes()));
Node rootnode = xmlObject.getDomNode().getFirstChild();
assertEquals("test",rootnode.getNodeName());
}
________________________________
From: Nicolai Odum [mailto:[EMAIL PROTECTED]
Sent: 15 September 2008 14:41
To: [email protected]
Subject: RE: Very simple question (I think)
Sorry bad example
It's was just suppose to be psudo code
String xml = "big xml document";
I have tried it with many big valid xml documents - without
luck.
/Nicolai
"Andrew Mansfield" <[EMAIL PROTECTED]>
15-09-2008 15:36
Please respond to
[email protected]
To
<[email protected]>
cc
Subject
RE: Very simple question (I think)
I think you need to parse a valid source document first. Then
you can get access to the underlying XmlObject.
Regards,
________________________________
From: Nicolai Odum [mailto:[EMAIL PROTECTED]
Sent: 15 September 2008 14:32
To: [email protected]
Subject: Very simple question (I think)
Hello
On xmlbeans.apache.org
<http://xmlbeans.apache.org/docs/2.0.0/guide/conGettingStartedwithXMLBeans.html>
it says that XMLBeans provide
<quote>
It provides a familiar Java object-based view of XML data
without losing access to the original, native XML structure
</quote>
I am using XMLBeans on a xml structure that is signed with a
hash value so *nothing* must change before the xml is invalid.
The question is: *HOW* do i get access to the original, native
XML structure.
because this doesn't work
String xml = "big xml document";
XmlObject parse = XmlObject.Factory.parse(xml);
String newXml = parse.xmlText();
if (xml.equals(newXml)
System.out.println("jubii");
else
System.out.println("damn");
Please help :-)
Cheers
Nicolai
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