<name>First Name & Last Name</name>

is simply not valid xml.
That is why you get an exception when you try to parse it.
The '&' needs to be escaped, e.g., as "&amp;".

The setSaveSubstituteCharacters option has nothing to do
with unmarshalling, only with marshalling.

-----Original Message-----
From: YesKay [mailto:keerthip...@yahoo.com] 
Sent: Wednesday, December 16, 2009 8:34 AM
To: user@xmlbeans.apache.org
Subject: XML Beans - Escape Chars


I'm trying to escaping & char and getting below exception... just wondering
what am I doing wrong? Any help will be greatly appreciated. Here is my
program.

Exception ==>

org.apache.xmlbeans.XmlException: error: Unexpected character encountered
(lex state 3): ' '
        at 
org.apache.xmlbeans.impl.store.Locale$SaxLoader.load(Locale.java:3471)
        at org.apache.xmlbeans.impl.store.Locale.parse(Locale.java:706)
        at 
org.apache.xmlbeans.impl.store.Locale.parseToXmlObject(Locale.java:690)
        at 
org.apache.xmlbeans.impl.store.Locale.parseToXmlObject(Locale.java:677)
        at
org.apache.xmlbeans.impl.schema.SchemaTypeLoaderBase.parse(SchemaTypeLoaderBase.java:208)
        at org.apache.xmlbeans.XmlObject$Factory.parse(XmlObject.java:633)

Program ==>

public class XMLBeansEscapeChars
{
        public static void main(String[] args)
        {
                try
                {
                String str = "<name>First Name & Last Name</name>";
                
                XmlOptionCharEscapeMap escapes = new XmlOptionCharEscapeMap();
                escapes.addMapping('&', XmlOptionCharEscapeMap.PREDEF_ENTITY);

                XmlOptions xmlOpts = new XmlOptions();
                xmlOpts.setSaveSubstituteCharacters(escapes);
                
                XmlObject xmlObj = XmlObject.Factory.parse(str, xmlOpts);
                
                System.out.println(xmlObj.xmlText());
                }
                catch (Exception ex)
                {               
                        ex.printStackTrace();
                }
        }
}

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