I'm sure I'm missing something here. Doesn't hibernate support enums anyway?

From my current AppFuse based project:

@Entity
@Table(name = "assets")
public class Asset extends BaseObject {
// ...
        @Enumerated(EnumType.STRING)
        @Column(length = 10, nullable=true)
        private Status status ;

// getters/setters blah....
}

and status is defined as:

public enum Status {
   PENDING,
   INPROGRESS,
   INCOMPLETE,
   UPLOADED,
   COMPLETE,
   FAILED,
   PROCESSING
}

works just fine.

Gareth
On 4 Jun 2007, at 15:01, celeraman+ wrote:


If you need to map Java 5 Enums to Hibernate using JPA annotations this is
you are looking for.


First, a sample POJO from AppFuse Persistence tutorial to demo how to use
the annotations.

--- cut here -------------------------------------
package org.appfuse.tutorial.model;

@Entity
@Table(name="t_person")
public class Person extends BaseObject {

  // Enumerations ---------------------------
    public enum Sex{

     MALE(1),
     FEMALE(2);

     private int value;

     Sex(int value) {
         this.value = value;
     }

     // the identifierMethod
     public int toInt() {
       return value;
     }

      // the valueOfMethod
      public  static Sex fromInt(int value) {
          switch(value) {
              case 1: return MALE;
              case 2: return FEMALE;
              default:
                      return UNKNOW;
          }
     }

     public String toString() {
       switch(this) {
         case MALE:
             return "Male";
         case FEMALE:
             return "Female";
       }
     }
   }



   // Attributes ---------------------------

   @Id
   @Column(name= "person_id")
   @GeneratedValue(strategy = GenerationType.AUTO)
   private Long id;

   @Column(name="person_firstname", length = 50, nullable = false)
   private String firstName;

   @Column(name="person_lastname", length = 50, nullable = false)
   private String lastName;

@Column(name= "person_sex", columnDefinition="integer", nullable = true) @Type(type = "org.appfuse.tutorial.commons.hibernate.GenericEnumUserType
",
       parameters = {
               @Parameter(
                   name  = "enumClass",
                   value = "org.appfuse.tutorial.model.Person$Sex"),
               @Parameter(
                   name  = "identifierMethod",
                   value = "toInt"),
               @Parameter(
                   name  = "valueOfMethod",
                   value = "fromInt")
               }
   )
   private IdentidadeDocTipos tipo;


   /*
   Getters and Setters ...
   */
}

2) Now, use the "Flexible solution - working version" (thanks to Martin
Kersten)
from the article Java 5 EnumUserType, see http://www.hibernate.org/272.html
to map the Sex attribute.

--- cut here -------------------------------------
package org.appfuse.tutorial.commons.hibernate;

import java.io.Serializable;
import java.lang.reflect.Method;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.Properties;

import org.hibernate.HibernateException;
import org.hibernate.type.NullableType;
import org.hibernate.type.TypeFactory;
import org.hibernate.usertype.ParameterizedType;
import org.hibernate.usertype.UserType ;

/**
* Implements a generic enum user type identified / represented by a single
identifier / column.
* <p><ul>
* <li>The enum type being represented by the certain user type must be
set
*        by using the 'enumClass' property.</li>
*    <li>The identifier representing a enum value is retrieved by the
identifierMethod.
*        The name of the identifier method can be specified by the
* 'identifierMethod' property and by default the name() method is
used.</li>
*    <li>The identifier type is automatically determined by
*        the return-type of the identifierMethod.</li>
*    <li>The valueOfMethod is the name of the static factory method
returning
* the enumeration object being represented by the given indentifier.
*        The valueOfMethod's name can be specified by setting the
'valueOfMethod'
*        property. The default valueOfMethod's name is 'valueOf'.</li>
* </p>
* <p>
* Example of an enum type represented by an int value:
* <code>
* public enum SimpleNumber {
*   Unknown(-1), Zero(0), One(1), Two(2), Three(3);
*   int value;
*   protected SimpleNumber(int value) {
*       this.value = value;
*       }
*
*   public int toInt() { return value; }
*   public SimpleNumber fromInt(int value) {
*         switch(value) {
*          case 0: return Zero;
*         case 1: return One;
*         case 2: return Two;
*         case 3: return Three;
*         default:
*                 return Unknown;
*     }
*   }
* }
* </code>
* <p>
* The Mapping would look like this:
* <code>
*    <typedef name="SimpleNumber" class="GenericEnumUserType">
*        SimpleNumber
*        toInt
*        fromInt
*    </typedef>
*    <class ...>
*      ...
*     <property name="number" column="number" type="SimpleNumber"/>
*    </class>
* </code>
*
* @author Martin Kersten
* @since 05.05.2005
*/
public class GenericEnumUserType implements UserType, ParameterizedType { private static final String DEFAULT_IDENTIFIER_METHOD_NAME = "name"; private static final String DEFAULT_VALUE_OF_METHOD_NAME = "valueOf";

   private Class<? extends Enum> enumClass;
   private Class<?> identifierType;
   private Method identifierMethod;
   private Method valueOfMethod;
   private NullableType type;
   private int[] sqlTypes;

   public void setParameterValues(Properties parameters) {
       String enumClassName = parameters.getProperty ("enumClass");
       try {
enumClass = Class.forName(enumClassName).asSubclass(Enum.class); System.out.println(">>>enumClass: " + enumClass.toString());
       } catch (ClassNotFoundException cfne) {
           throw new HibernateException("Enum class not found", cfne);
       }

       String identifierMethodName =
parameters.getProperty("identifierMethod", DEFAULT_IDENTIFIER_METHOD_NAME);

       try {
identifierMethod = enumClass.getMethod(identifierMethodName, new
Class[0]);
           identifierType = identifierMethod.getReturnType();
           // XXX
           System.out.println (">>>identifierMethod: " +
identifierMethod.toString());
           System.out.println(">>>identifierType: " +
identifierType.toString());
       } catch (Exception e) {
           throw new HibernateException("Failed to obtain identifier
method", e);
       }

type = (NullableType) TypeFactory.basic(identifierType.getName());

       if (type == null)
throw new HibernateException("Unsupported identifier type " +
identifierType.getName ());

       sqlTypes = new int[] { type.sqlType() };

String valueOfMethodName = parameters.getProperty("valueOfMethod",
DEFAULT_VALUE_OF_METHOD_NAME);
System.out.println(">>>valueOfMethodName: " + valueOfMethodName);

       try {
           valueOfMethod = enumClass.getMethod(valueOfMethodName, new
Class[] { identifierType });
System.out.println(">>>valueOfMethod: " + valueOfMethod.toString
());
       } catch (Exception e) {
throw new HibernateException("Failed to obtain valueOf method",
e);
       }
   }

   public Class returnedClass() {
       return enumClass;
   }

public Object nullSafeGet(ResultSet rs, String[] names, Object owner)
throws HibernateException, SQLException {
       Object identifier = type.get(rs, names[0]);
       if (identifier == null) {
           return null;
       }

       try {
return valueOfMethod.invoke(enumClass, new Object[] { identifier
});
       } catch (Exception e) {
throw new HibernateException("Exception while invoking valueOf
method '" + valueOfMethod.getName() + "' of " +
                   "enumeration class '" + enumClass + "'", e);
       }
   }

public void nullSafeSet(PreparedStatement st, Object value, int index)
throws HibernateException, SQLException {
       try {
           if (value == null) {
               st.setNull(index, type.sqlType());
           } else {
               Object identifier = identifierMethod.invoke(value, new
Object[0]);
               type.set(st, identifier, index);
           }
       } catch (Exception e) {
           throw new HibernateException("Exception while invoking
identifierMethod '" + identifierMethod.getName () + "' of " +
                   "enumeration class '" + enumClass + "'", e);
       }
   }

   public int[] sqlTypes() {
       return sqlTypes;
   }

   public Object assemble(Serializable cached, Object owner) throws
HibernateException {
       return cached;
   }

   public Object deepCopy(Object value) throws HibernateException {
       return value;
   }

public Serializable disassemble(Object value) throws HibernateException
{
       return (Serializable) value;
   }

public boolean equals(Object x, Object y) throws HibernateException {
       return x == y;
   }

   public int hashCode(Object x) throws HibernateException {
       return x.hashCode();
   }

   public boolean isMutable() {
       return false;
   }

   public Object replace(Object original, Object target, Object owner)
throws HibernateException {
       return original;
   }
}
--- cut here -------------------------------------

So, that's it! Maybe this helps someone!

Thank you all AppFusers!
--
celeraman +
--
View this message in context: 
http://www.nabble.com/Java-5-Enums-Persistence-%3A%3A-How-to-tf3865408s2369.html#a10950327
Sent from the AppFuse - User mailing list archive at Nabble.com.

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