alibehzadian wrote:
>
> If you want to get current logged in user, use the code snippet below:
> User currentUser = null;
> SecurityContext ctx = SecurityContextHolder.getContext();
> if (ctx.getAuthentication() != null) {
> Authentication auth = ctx.getAuthentication();
> if (auth.getPrincipal() instanceof UserDetails) {
> currentUser = (User) auth.getPrincipal();
> } else if (auth.getDetails() instanceof UserDetails) {
> currentUser = (User) auth.getDetails();
> } else {
> throw new AccessDeniedException("User not properly
> authenticated.");
> }
> }
> Ali Behzadian Nejad.
>
as you told that you're using spring then perhaps you can do as same that I
do, that I create a class, I put it in src/service/.../util/, I call it
UserUtil because I call it often in my application, it return the logged in
user, with parameter UserManager that already appfuse had. and this is my
full code of that class:
public final class UserUtil {
public synchronized static User getCurrentUser(UserManager mgr) {
Object obj =
SecurityContextHolder.getContext().getAuthentication().getPrincipal();
String username;
if (obj instanceof UserDetails) {
username = ((UserDetails) obj).getUsername();
} else {
username = obj.toString();
}
return username != null ? mgr.getUserByUsername(username) :
null;
}
}
HTH
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