Hi,

If camel can't send the JMS message into the jms queue, it will throw the exception , and camel will use the default error handler[1] (which will try to redeliver the message few times) to deal with this error, then the jetty consumer can get the error and send back an error message to the client. So If you just want to send the OK message back to the jetty endpoint, you may need to the work like this
from("jetty:http://localhost:9080/myapp/myservice";)
  .process(new Processor() {...})
   // set the exchange pattern, since there is no response from jms queue
  .inOnly()
  .to("jms:queue:some_queue")
  // set the out message for jetty consumer to send back to client
  .inOut().setBody(constant("OK"));

[1]http://camel.apache.org/error-handler.html

Willem

janylj wrote:
I don't think it works. My exact route is:

from("jetty:http://localhost:9080/myapp/myservice";)
.process(new Processor() {...})
.to("jms:queue:some_queue")
.to("http://localhost:9080/myapp/myservice";);

I still got the error said,
org.apache.camel.ExchangeTimedOutException: The OUT message was not received
within: 20000 millis on the exchange:

Basically I would like my starting endpoint receive 200 status ok when send
jms successfully or 500 error when send jms failed. How to do that?

Thanks a lot.


Claus Ibsen-2 wrote:
On Wed, Aug 12, 2009 at 7:01 PM, janylj<[email protected]> wrote:
Thanks a lot, Willem. It works using inOnly()

willem.jiang wrote:
from("jetty ....").process(...).inOnly().to("jms:queue")

How to make it send a HttpResponse only if sending JMS message is
successfully. I tried to list the same jetty endpoint in the end, but it
doesn't work. Please advise. Thanks again.

from("jetty ....").process(...).to("jms:queue").to("jetty....")

jetty is only used as a consumer, eg you can only use it in the from node.
So when you want to call some external HTTP service use the http
component instead

from(jetty).to(http)  = OK

from(jetty).to(jetty) = NO OK


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Claus Ibsen
Apache Camel Committer

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