Hi Johan,
You can do this in the following way
from("somewhere")
.process(new Processor() {
public void process(Exchange exchange) throws Exception {
String payload = exchange.getIn().getBody(String.class);
// get URI from payload body and set it in header (optional if
such a header exists)
exchange.getIn.setHeader("targetURI",...)
exchange.getIn().setBody("Changed body");
}
})
.marshal(...) // Not sure what marshalling you need here
.process(new Processor() {
public void process(Exchange exchange) throws Exception {
String payload = exchange.getIn().getBody(String.class);
String targetURI = exchange.getIn().getHeader("targetURI");
ProducerTemplate producer = new ProducerTemplate(...);
Exchange result = producer.send(targetURI , exchange);
...
}
}).
Cheers,
Ashwin...
Johan Haleby wrote:
>
> I found out by myself. I simply put the uri in a header and simply pass
> the header to the recipient list.
>
>
> Johan Haleby wrote:
>>
>> Hi,
>>
>> I have a use-case where I must extract a endpoint uri from an object,
>> marshal the object to an unknown format and then send the result to the
>> extracted uri. Is there a built-in way to do this or do I have to
>> manually persist the extract endpoint and retrieve a dynamic router or
>> something? Here's some pseudo code describing what I'm looking for:
>>
>> from("somewhere").extractURIFromConsumedObject().
>> marshal(encodeToUnknownFormat).to("uriThatWasExtractedFromTheConsumedObject");
>>
>> Thanks,
>> /Johan
>>
>
>
-----
---
Ashwin Karpe, Principal Consultant, PS - Opensource Center of Competence
Progress Software Corporation
14 Oak Park Drive
Bedford, MA 01730
---
+1-972-304-9084 (Office)
+1-972-971-1700 (Mobile)
----
Blog: http://opensourceknowledge.blogspot.com/
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