On Thu, Aug 16, 2012 at 2:32 PM, Joe San <codeintheo...@gmail.com> wrote:
> I have decided to use JAXB instead of xStream. My route definition looks
> like this:
>
> final JaxbDataFormat jaxb = new
> JaxbDataFormat("com.example.filexml");
> context.addRoutes(new RouteBuilder() {
> public void configure() {
> from("file://my.xml").unmarshal(jaxb).bean(new
> ProcessorBean()).to("file://my.xml");
> }
> });
>
> How do I get hold of the UnMarshalled Java Object (say Person.java) in my
> ProcessorBean. Also, when I use a bean for Processing, how does Camel know
> which method to invoke in that bean?
>
If you use the Camel Processor, then you get it from the Exchange, eg
the input message. On the message body.
http://camel.apache.org/processor.html
For invoking pojos (beans) instead, then read through the Camel docs
about bean component / bean parameter binding / etc.
http://camel.apache.org/bean-binding.html
If you have a copy of Camel in Action book, then chapter 3 and 4 is a
great source for all this kind of stuff. And explained in much detail.
> Regards,
> Jothi
>
> On Thu, Aug 16, 2012 at 1:56 PM, Joe San <codeintheo...@gmail.com> wrote:
>
>> Guys,
>>
>> I have a route which is defined as below:
>>
>> from("file://my.xml").marshal().xstream("UTF-8").bean(new
>> ProcessorBean()).to("file://my.xml");
>>
>> All I want to do is access the my.xml in my ProcessorBean. Where and how
>> do I specify the Java object which will be filled with the values in the
>> xml file?
>>
>> Regards,
>> Jothi
>>
--
Claus Ibsen
-----------------
FuseSource
Email: cib...@fusesource.com
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Blog: http://davsclaus.com
Author of Camel in Action: http://www.manning.com/ibsen
