exchange.in returns an Object, so there is no getHeader method
available on that.
There is an exchange.header but like I said it seems to return some
DSL construct that I can't figure out how to get the value out of.
On 1 November 2012 09:52, Willem jiang <willem.ji...@gmail.com> wrote:
>
> in.getHeader("header-name") should work for you.
>
> --
> Willem Jiang
>
> Red Hat, Inc.
> FuseSource is now part of Red Hat
> Web: http://www.fusesource.com | http://www.redhat.com
> Blog: http://willemjiang.blogspot.com (http://willemjiang.blogspot.com/)
> (English)
> http://jnn.javaeye.com (http://jnn.javaeye.com/) (Chinese)
> Twitter: willemjiang
> Weibo: willemjiang
>
>
>
>
>
> On Thursday, November 1, 2012 at 5:48 PM, Willem jiang wrote:
>
>> If you can access the exchange directly, you can use exchange.in
>> (http://exchange.in)("header-key") to access the in message header.
>>
>>
>> --
>> Willem Jiang
>>
>> Red Hat, Inc.
>> FuseSource is now part of Red Hat
>> Web: http://www.fusesource.com | http://www.redhat.com
>> Blog: http://willemjiang.blogspot.com (http://willemjiang.blogspot.com/)
>> (English)
>> http://jnn.javaeye.com (http://jnn.javaeye.com/) (Chinese)
>> Twitter: willemjiang
>> Weibo: willemjiang
>>
>>
>>
>>
>>
>> On Thursday, November 1, 2012 at 5:34 PM, Sam (Stephen Samuel) wrote:
>>
>> > Hi all,
>> >
>> > How can I get the value of a header from an exchange using the Scala
>> > DSL. Maybe I'm going mad but
>> >
>> > in.header("header-name")
>> >
>> > gives me a variable of type HeaderExpression or HeaderLanguage (can't
>> > remember which) and I can't seem to get the "value" from that ?
>>
>
>
>
--
-Sam
