Hello
I'm writing my routes in XML. Currently, I have a route in DSL
from("direct:operation-1")
.to("bean:ExportOrdersComponent")
.split().message()
.to("bean:RenderOrderComponent")
.to("bean:SaveOrderComponent")
How should I convert this to XML? I tried
<route>
<from uri="direct:operation-1" />
<to uri="bean:ExportOrdersComponent" />
<split message="true">
<to uri="bean:RenderOrderComponent" />
<to uri="bean:SaveOrderComponent" />
</split>
</route>
But I get an error
Failed to create route operation-1 at: >>> Split[null ->...
Can somebody please help me correctly build XML route?
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