Hey John,
I'm using org.apache.cxf:cxf-codegen-plugin in pom.xml, it builds all the
classes in let's say com.somecompany.model package. Then the route looks like
this:
SoapJaxbDataFormat soap = new SoapJaxbDataFormat(com.somecompany.model.
ServicePort.class.getPackage().getName(), new
ServiceInterfaceStrategy(ServicePort.class, true));
from("direct:sendToSoap")
.marshal(soap)
.convertBodyTo(String.class)
.log(LoggingLevel.DEBUG, this.getClass().getName(), "request:
${body}")
.setHeader(Exchange.CONTENT_TYPE, constant("text/xml"))
.to("https4:some-company-server/some-ws-endpoint")
.convertBodyTo(String.class)
.log(LoggingLevel.DEBUG, this.getClass().getName(), "response:
${body}")
.unmarshal(soap);
This is probably not the most kosher way of doing this, but it works and is
pretty straightforward (and there is no Spring).
Cheers,
Dmitry
-----Original Message-----
From: John F. Berry [mailto:[email protected]]
Sent: Monday, November 4, 2019 12:55 PM
To: [email protected]
Subject: Java DSL cxf SOAP call (client)..
OK.. I've tried to google this to death to avoid asking something so
embarrassing.. but to no avail..So, without making eye contact with anyone
here.. How do I construct a call using cxf and utilizing wsdl2java in Java DSL?
I've had a project that receives a message and decodes a base64 encoded pdf to
a filesystem and updates MS SQL with the properties of that action.. Now we
are changing systems and the base64 encoded pdf will remain encoded, but
marshalled with some data properties placed into XML for a SOAP call. I have
the vendor's WDSL and have defined that in the cxf plugin, I expected to see a
code example like:
.encode(??"service name"??).to(cxf:"uri","service") and that to be it... but
everyone with an example (with cxf, wdsl2java, and cxf plug-in) is showing it
in spring. The WSDL being defined in cxf I would assume would expose my XML
fields and the specific "service calls" to simply be referenced..
OK.. I've said that.. I'll go back to my kindergarten room and play blocks
now.. Thanks!
