I'm following the instructions at
http://wiki.cocoondev.org/Wiki.jsp?page=IntegrateAServlet and I receive a
Resource not found error:
org.apache.cocoon.ResourceNotFoundException: Could not get resource
file:/F:/Cocoon/webapp/Amazon/AmazonServlet:
org.apache.excalibur.source.SourceNotFoundException:
file:/F:/Cocoon/webapp/Amazon/AmazonServlet doesn't exist.
My servlet spits out HTML that I mean to convert to XHTML to send through my
pipeline.
Here's my pipeline snippet from my Amazon subsitemap:
<map:pipeline match="AmazonService">
<map:generate src="AmazonServlet" type="html" />
<map:serialize />
</map:pipeline>
Here's my web.xml snippet:
<servlet>
<!-- name used to refer to servlet -->
<servlet-name>AmazonService</servlet-name>
<!-- fully-specified class name of servlet -->
<servlet-class>AmazonServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>AmazonService</servlet-name>
<!-- the URL path at which the servlet is mounted -->
<url-pattern>/Amazon/AmazonService</url-pattern>
</servlet-mapping>
The error shows that my page request is properly mapped to the
AmazonServlet. I've dropped the .jar into my cocoon-home/WEB-INF/lib. The
servlet is not part of a package for this simple example, hence the simple
servlet-class. Of course I've restarted Jetty before testing.
Question... The error shows that Cocoon is looking for the AmazonServlet in
a particular directory. I do have a copy of the class there, but it's also
packaged in a .jar in the lib directory. The Wiki page says it should be
looking for the file in the .jar, so why the error message?
Any hints? Thanks!
Jeff
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
