So, I do not parse the String after.
I suggest you to look at the util.xsl of your cocoon. There is a link with the method XSPUtil of cocoon.
Also see the API : http://cocoon.apache.org/2.1/apidocs/org/apache/cocoon/components/language/markup/xsp/XSPUtil.html
That's all I can do.
At 18:03 19/12/2003 +0100, you wrote:
Hi Lionel,
I bookmarked these usefull links, but I'm afraid this won't help me : the unescaped String will be re-escaped by the Cocoon serializer...
I must parse the String and "Saxize" '\n' characters in contentHandler.startElement("br"); contentHandler.endElement("br");
Maybe some xsp utils could do that, but I didn't found... <util:include-expr> and brothers only work with full xml documents...
-- Olivier
On 19/12/2003 16:28, Lionel Crine wrote:Hi,
I don
I was looking for the oppoite of your question and I have found some useful methods in common-lang-2.0.
You can get it there :
http://jakarta.apache.org/site/binindex.cgi?Preferred=http%3A%2F%2Fapache.crihan.fr%2Fdist
In StringEscapeUtils, you ll find some unescape methods like <file:///D:/source_software/java/commons-lang-2.0/docs/api/org/apache/commons/lang/StringEscapeUtils.html#unescapeXml%28java.lang.String%29>unescapeXml(<http://java.sun.com/products/jdk/1.2/docs/api/java/lang/String.html>String str)
You can find the API there :
http://www.generationjava.com/maven/jakarta-commons/lang/apidocs/index.html
or inside the jar.
Hope that Help. Lionel
At 14:01 19/12/2003 +0100, you wrote:
Hi all !
I would like to output a java String in an XSP page, containing some html tags that I would like not to be escaped.
How could it be possible ?
I tried <util:include-expr>, but it seems only to work with full XML document, not a fragment.
To be more precise, my contains "\n" caracters that I want to translate to <br/> for html output.
Thanks,
-- Olivier BILLARD
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