Re: File upload/Multipart form

[Lionel Crine]

Here is a sample code :

HttpServletRequest request = (HttpServletRequest) 
objectModel.get(HttpEnvironment.HTTP_REQUEST_OBJECT);
contentType = request.getContentType();
if (contentType == null) {
contentType = parameters.getParameter("defaultContentType", null);
}
if (contentType == null) {
throw new Exception("ERROR");
} else if (contentType.startsWith("application/x-www-form-urlencoded") || 
contentType.startsWith("multipart/form-data")) {
String parameter = parameters.getParameter(FORM_NAME, null);
if (parameter == null) {
throw new Exception("ERROR");
}
String sXml = request.getParameter(parameter);
inputSource = new InputSource(new FileInputStream(sXml));

} else if (contentType.startsWith("text/plain") || 
contentType.startsWith("text/xml") || 
contentType.startsWith("application/xml")) {

len = request.getContentLength();
if (len > 0) {
PostInputStream anStream = new PostInputStream(request.getInputStream(), len);
inputSource = new InputSource(anStream);
} else {
throw new SyspeoException("ERROR);
}
} else {
throw new SyspeoException("ERROR);
}
InputStream is = inputSource.getByteStream();



This code is adapted from StreamGenerator.
An action can do the same.
Lionel

At 15:04 22/01/2004 +0100, you wrote:
Hello list ;=)
Do you know if Cocoon handles multipart form like*
<form action="doaction">
        <input type="file" />
        <input type="text"/>
</form>
I can't find the answer in the documentation.

Thanks for your answer.

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Lionel CRINE
Ing�nieur Syst�mes documentaires
Soci�t� : 4DConcept
22 rue Etienne de Jouy 78353 JOUY EN JOSAS
Tel : 01.34.58.70.70 Fax : 01.39.58.70.70
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