Ah now I understand your concern. Use <xsl:copy-of select="content"/> or <xsl:copy-of select="content/*"/>.
Markus > -----Original Message----- > From: Kirk Storer [mailto:[EMAIL PROTECTED] > Sent: Thursday, March 04, 2004 9:00 PM > To: [EMAIL PROTECTED] > Subject: Re: Easy way to include xhtml when transforming xml to xhtml > > > Ok, I will try to explain this better. > I am using two files as sources, combined via aggregate in the sitemap. > The content of one of the files will be contained in <menu></menu> > The content of the other file will be contained in <content></content> > Both of these are then inside of <page> </page> > > I want to process the xml within <menu> into xhtml. > I merely want to use what is in the <content> tags as it is, it is > already xhtml. > > > this is an extremely simplified version of the xsl file > ---------------------------------------------- > <xsl:template match="page"> > <xsl:for-each select="menu"> > do whatever > </xsl:for-each> > > <xsl:value-of select="content"/> > </xsl:template> > ----------------------------------------------- > If i use <xsl:value-of select="content"/> it displays the text, but not > all of the markup tags > > How can it get it to include all of the markup tags that are in the > file, such as > <p> </p> > <ul><li></li></ul> > etc. > > Thanks, > Kirk > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
