Re: JXTemplate and XML "fields"

[Christopher Oliver]

Another approach is to stream it into a SaxBuffer (which implements 
XMLizable and therefore will be automatically streamed by 
JXTemplateGenerator). Something like this:

// parse "string" sending SAX events to "consumer"
function toSAX(string, consumer) {
 var is = new org.xml.sax.InputSource(new java.io.StringReader(string));
 var parser = null;
 try {
   parser = 
cocoon.getComponent(org.apache.excalibur.xml.sax.SAXParser.ROLE);
   // Create a filter to remove the start document and end document events
   var contentHandlerWrapper =
     new org.apache.cocoon.xml.ContentHandlerWrapper() {
       startDocument: function() {
         // inhibit this event
       }
       endDocument: function() {
         // inhibit this event
       }
   };
   contentHandlerWrapper.contentHandler = consumer;
   contentHandlerWrapper.lexicalHandler = consumer;
   parser.parse(is, contentHandlerWrapper);
 } finally {
   if (parser != null) {
     cocoon.releaseComponent(parser);
   }
 }
}

I guess you could even avoid the sax buffer and stream it directly in 
the template:

// flowscript fragment
var message = ...;
sendPage("page.html", {message: message, streamer: {toSAX: toSAX}});
// jx template fragment
<jx:template xmlns:jx="http://apache.org/cocoon/templates/jx/1.0";>
...
<jx:set var="ignored" value="${streamer.toSAX(message.content, 
cocoon.consumer}}"/>
...
</jx/template>

Chris

Ugo Cei wrote:

Leszek Gawron wrote:

Imagine I have a bean fetched from database. Call it a Message. A 
Message has
a String getContent() method. Now this string contains not a plain 
text but an
X(HT)ML piece. What is the most elegant, fastest and most convenient 
way to
make JXTemplate treat it as a node instead of displaying the tags as 
text ?
    lg

Parse the string, get the DOM and pass it to the template.

    Ugo



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