Re: How do I find out why DOM parser fails

[Olivier Billard]

Hi Colin,
You can catch thrown exceptions and log it.
A simple
try {
    ...
} catch (exception) {
    print("Error :" + exception.message);
} finally {
    ...
}
should help you for development if you're using the embedded jetty (look 
at the jetty output)

--
Olivier Billard
Colin Paul Adams wrote:
In the CForms xml binding script, there is code similar to:
function loadDocument(uri) {
    var parser = null;
    var source = null;
    var resolver = null;
    try {
        parser = cocoon.getComponent(Packages.org.apache.excalibur.xml.dom.DOMParser.ROLE);
        resolver = cocoon.getComponent(Packages.org.apache.cocoon.environment.SourceResolver.ROLE);
        source = resolver.resolveURI(uri);
        var is = new Packages.org.xml.sax.InputSource(source.getInputStream());
        is.setSystemId(source.getURI());
        var document = parser.parseDocument(is);
	cocoon.log.debug (document);
	return document;     
    } 
    finally {
        if (source != null)
            resolver.release(source);
        cocoon.releaseComponent(parser);
        cocoon.releaseComponent(resolver);
    }
}

but I am getting a value of null for the document variable.
How do I find out why the parser is failing to parse the document
content (which should be perctly valid xml)?

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