I've got a form with an invisible item and a radio box that will set it to
active. It works fine except the label doesn't appear. The definition looks
something like:
(On the widget):
<fd:on-create>
<fd:javascript>
this.setState(Packages.org.apache.cocoon.forms.formmodel.WidgetState.INVISIBLE);
</fd:javascript>
</fd:on-create>
(On the activating widget):
<fd:on-value-changed>
<fd:javascript>
var dod_widget = event.source.parent.lookupWidget("dod");
if(event.source.value == "0")
{
dod_widget.setState(Packages.org.apache.cocoon.forms.formmodel.WidgetState.INVISIBLE);
dod_widget.value = "";
}
else //1
{
dod_widget.setState(Packages.org.apache.cocoon.forms.formmodel.WidgetState.ACTIVE);
}
</fd:javascript>
</fd:on-value-changed>
Is there anything else I need to set to make the label appear? I've tried using
the column group layout for it and just "manually" having the label in the form
but neither seem to show the label when the widget becomes active.
Thanks,
Gary
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