Jason Johnston wrote: > First you assign the 'useless' variable a String value, then you > create the continuation. When you resume the continuation the first > time, you re-assign the 'useless' variable so that it now holds an > Array value (String.split() returns an Array). When you resume the > continuation again, you try to call .split() on the 'useless' var, > which is now an Array, and the error is appropriately thrown since an > Array has no such method.
When I resume the continuation again, I'm resuming it from before assigning the array, so one would think that useless (which is a local variable) would still contain a string! What am I missing? Toby --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
