OK, the solution is:
ON EVERY form.showForm(....);
var cont = form.showForm();
cont.invalidate
At this point, when you "go back" in your browser: you can see all the
prvious windows.. but in these windows you can not click on for instance a
submit button!!! so OK, all the continuations are invalidated!!!
But, i don't want users to go back after a "logout".. beceause there is
still private information visible..
So, beside invalidating the continuations.. is it possible to avoid people
using the "go back" button?
thanks and greetings..
Jason Johnston-3 wrote:
>
> The cocoon.exit() function only stops the current script execution, it
> does not affect any continuations that have already been created. To do
> that you need to invalidate those continuations.
>
> It looks like you're trying to implement a logout process... is there
> any reason why you can't just invalidate the whole session? If you've
> got your continuations manager (see cocoon.xconf) configured to attach
> continuations to the session, then they will automatically be
> invalidated along with the session.
>
> If for some reason you can't invalidate the session, then I think you
> need to crawl up the continuation's ancestry and invalidate the oldest,
> which will then automatically invalidate all the descendants. Something
> like:
>
> var kont = registrationForm.showForm(...
> ...
> var oldest = kont;
> while(oldest.getParent() != null) {
> oldest = oldest.getParent();
> }
> oldest.invalidate();
>
> Hope that's on the right track.
> --Jason
>
>
> jantje wrote:
>> Hey! thanks for searching and thinking with me.. but no, i can still use
>> the
>> "back" option in my browser :-(
>>
>> thanks!
>>
>>
>> Dev at weitling wrote:
>>> Hi Jan!
>>>
>>> After I stumbled through the wood not seeing the wood for the trees, it
>>> now may be I can help :-)
>>>
>>> Try using cocoon.exit() to exit the flow PLUS
>>> WebContinuation.invalidate().
>>>
>>> Reijn made me look here:
>>> http://cocoon.apache.org/2.1/userdocs/flow/api.html#cocoon
>>>
>>> Greetings,
>>> Florian
>>>
>>> jantje wrote:
>>>> I think it is not working beceause i can still use the "back" button in
>>>> my
>>>> browser!!!
>>>>
>>>> OK, maybe no new continuation is created.. BUT, with the "BACK" -
>>>> button
>>>> I
>>>> can still enter a previously created continuation..
>>>>
>>>> Maybe there is no function to really STOP the flow, in a cocoon
>>>> flowscript?
>>>>
>>>> Does someone know the answer?
>>>>
>>>> Greetings, Jan from Belgium
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>> Jeroen Reijn wrote:
>>>>
>>>>> Hi Jantje,
>>>>>
>>>>> why do you think the cocoon.exit function is not working? Does it not
>>>>> exit
>>>>> the flowscript without creating a continuation?
>>>>>
>>>>> Regards,
>>>>>
>>>>> Jeroen Reijn
>>>>>
>>>>> -----Original Message-----
>>>>> From: jantje [mailto:[EMAIL PROTECTED]
>>>>> Posted At: Thursday, September 14, 2006 2:34 PM
>>>>> Posted To: Cocoon User List
>>>>> Conversation: cocoon.exit();
>>>>> Subject: cocoon.exit();
>>>>>
>>>>>
>>>>>
>>>>> Hi there,
>>>>>
>>>>> I think the cocoon.exit() function is not working? how can I check
>>>>> this?
>>>>>
>>>>> My code is:
>>>>>
>>>>> function registration() {
>>>>> var varContinue = true;
>>>>> while(varContinue) {
>>>>> var registrationForm = new
>>>>> Form("cocoon:/formDefinition/registration.xml");
>>>>> var rModel = registrationForm.getModel();
>>>>> rModel.date = new java.util.Date();
>>>>> registrationForm.showForm("registration/"
>>>>> + cocoon.request.get("identificaton")
>>>>> + "-"
>>>>> + cocoon.request.get("password")
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + "-"
>>>>> + "SB"
>>>>> + ".display");
>>>>> if(registrationForm.submitId == "logout") {
>>>>> cocoon.request.setAttribute("form1",
>>>>> registrationForm.getWidget());
>>>>> //cocoon.sendPage("form1-success-pipeline.xsp");
>>>>> cocoon.sendPage("registration-success");
>>>>> varContinue = false;
>>>>> cocoon.exit();
>>>>> }
>>>>> }
>>>>>
>>>>> }/*
>
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