Urs Iwert wrote:
Just add a line for each parameter in the xsl stylesheet
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:param name="someParam"/>
<xsl:param name="otherParam"/>
<xsl:template match="abct">
<xsl:if test="$someParam='cocoon:/patternC' ">
<dosomthing />
</xsl:if>
</xsl:template>
Hi Urs!
Maybe I didn't make it clear but I want to have the content of the
pipeline cocoon:/patternC and not the string "cocoon:/patternC"
UI
-----Ursprüngliche Nachricht-----
Von: ypomonh [mailto:[EMAIL PROTECTED]
Gesendet: Freitag, 11. Mai 2007 16:54
An: [email protected]
Betreff: (newbie) Access parameter passed to an XSL transformation from
stylesheet
I have a simple pipelineQ
<map:pipeline>
<map:match pattern="patternA">
<map:generate src="cocoon:/patternB"/>
<map:transform src="style.xsl">
<map:parameter name="someParam" value="cocoon:/patternC"/>
<map:parameter name="otherParam" value="cocoon:/patternC"/>
</map:transform>
<map:serialize type="xml"/>
</map:match>
</map:pipeline>
and I want to handle the parameter "someParam" in my style.xsl:
<xsl:variable name="myVariable">
<xsl:value-of select="someParam/nodeA"/>
</xsl:variable>
but it returns empty.
What is the correct way to access a parameter passed to an XSL transformation
from within the XSL stylesheet..?
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