hmm.. I did that. But not like a file...not like a stream... just a text in
POST parameter.
pipeline:
<map:match pattern="upload/myxsp">
<map:generate src="upload/myxsp.xsp" type="serverpages"/>
<map:serialize type="xml"/>
</map:match>
-----
for test myxsp.html:
<html>
<body>
<form action="http://localhost:80/upload/myxsp"; method="post"
enctype="multipart/form-data">
File: <input type="text" name="uploadfile">
<input type="submit"/>
</body>
</html>
-----
as example... myxsp.xsp:
<?xml version="1.0"?>
<xsp:page language="java" xmlns:xsp="http://apache.org/xsp";>
<root>
<xsp:logic>
try {
String foo = request.getParameter("uploadfile");
System.out.println(foo);
javax.xml.parsers.DocumentBuilderFactory factory =
javax.xml.parsers.DocumentBuilderFactory.newInstance();
javax.xml.parsers.DocumentBuilder builder = factory.newDocumentBuilder();
org.w3c.dom.Document doc = builder.parse(new
java.io.ByteArrayInputStream(foo.getBytes()));
org.w3c.dom.NodeList catlist =
doc.getDocumentElement().getElementsByTagName("category");
for (int i = 0; i < catlist.getLength(); i++)
{
org.w3c.dom.Node boo = catlist.item(i);
<xsp:content>
<xsp:expr>boo</xsp:expr>
</xsp:content>
}
}catch(java.lang.Exception e)
{
System.out.print(e.toString());
}
</xsp:logic>
</root>
</xsp:page>
-------------
but.......but I don't need to put xml to parameter.
I need to take a Content of request. But cocoon's HttpRequest hasn't
.getContent(). There is getInputStream, but I can't to understand how to use
that.
--
View this message in context:
http://www.nabble.com/POST-.xml-tp15517307p15561431.html
Sent from the Cocoon - Users mailing list archive at Nabble.com.
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
