Hi, Benjamin
Benjamin Boksa-2 wrote:
>
> I use the following code to access the currently authenticated User in
> flowscript:
>
> var appUtil =
> cocoon.createObject('org.apache.cocoon.auth.ApplicationUtil');
> var user = appUtil.getUser();
>
> The last call returns an instance of my User object which implements
> the org.apache.cocoon.auth.User interface. Using that interface you
> should be able to develop a specific User class for your application.
> A good starting point are Alessandro's examples [1].
>
Thank you very much for this information. That worked out of the box.
I only needed to tweek my setup a bit for my purposes:
I added this to my test-application context : (don't worry,
the final application will use another authentication class ;-)
===== application-context.xml ===================================
<bean name="org.apache.cocoon.auth.SecurityHandler/simple"
class="org.apache.cocoon.auth.impl.SimpleSecurityHandler"
scope="singleton">
<property name="userProperties">
<value>
manager=mana
manager.roles=admin_admin
manager.name=King Salomon
</value>
</property>
</bean>
<bean name="org.apache.cocoon.auth.Application/cocoon-app"
class="org.apache.cocoon.auth.impl.StandardApplication"
scope="singleton">
<property name="securityHandler"
ref="org.apache.cocoon.auth.SecurityHandler/simple"/>
==== end application-context.xml
=============================================
I needed the user's true name, so i simply added another property
"manager.name=<full name>"
to the security-handler bean above. And i was able to retrieve the full name
from within the flowscript
below:
function bookingPage()
{
var appUtil =
cocoon.createObject('org.apache.cocoon.auth.ApplicationUtil');
var user = appUtil.getUser();
var userName= user.getAttribute("name");
cocoon.sendPage("booking.jx", { userId: user.id, userName: userName } );
}
It works like a charm! Thanks again!
regards,
hussayn
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